Answer:
d = square root of {(x2 - x1)^2 + (y2-y1)^2}
Explanation:
If you're referring to math-
the distance is equal to (the second x value minus the first x value)^2 plus (the second y value minus the first y value)^2
For example: this is my imaginary ordered pair, I want to find the distance between the points- (2,4) and (3,6)
So d= (3-2)^2 - (6-4)^2 all under a square root
3-2 is = to 1, and 1 squared is just 1.
6-4 is = to 2, and 2 squared is 4.
4+1 is = 5.
So your answer would be the square root of 5.
If your answer ended up as, for example, the square root of 16, you would go a step further and your answer, or distance would be 4, since 4^2 is 16
