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IRINA_888 [86]
3 years ago
5

What do the Tuck boys do when they arrive home? A. They make lunch for Winnie. B. They hug their father. C. They jump in the lak

e. D. They ride their horse.
SAT
2 answers:
AysviL [449]3 years ago
8 0
The Tuck Boys C. They jump in the lake
Sholpan [36]3 years ago
7 0
C. They jump in the lake.
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Which statement proves that quadrilateral uwxy is a parallelogram.
Tanya [424]

Parallelograms are shapes that have 4 sides, where the opposite sides are congruent and parallel

<h3>How to determine a parallelogram</h3>

For a shape to be a parallelogram, then the following must be true

  1. The opposite side lengths are congruent
  2. The opposite side lengths are parallel
  3. The diagonals bisect each other

<h3>The proof statement</h3>

The above statements in (a) above mean that:

The statements that prove that quadrilateral uwxy is a parallelogram are

  • Diagonals UX and WY bisect each other
  • Sides UW and XY are congruent
  • Sides UW and XY are parallel.
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Read more about parallelograms at:

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4 0
3 years ago
Altitudes $\overline{ad}$ and $\overline{be}$ of acute triangle $abc$ intersect at point $h$. if $\angle ahb = 128^\circ$ and $\
DENIUS [597]

The Angle HCA is equal to 52°. This is arrived at using the knowledge of the Total value of Angles in a Triangle and the Total Value of Angles in a Polygon.

<h3>What other principles were used to arrive at the answer?</h3>

The other principles of mathematics that were used to arrive at the above answer are:

  • Total Angles on a straight line;
  • Total Angles on a point; and
  • Line segments.

<h3>What are the Steps to the Solution? </h3>

Step 1 - Recall that we have been given Angles AHB and BAH to be 128° and 28° respectively.

We also know that:

  1. The sum of angles in a triangle is 180°;...................A
  2. The sum of angles on a straight line is 180°;.........B
  3. The sum of angles in a polygon is 360°; while.....C
  4. The total sum of angles at a point is 360°.............D

Since A...therefore:

When ∠AHB (128°) and ∠BAH are taken from 180° we have DBA = ∠28°.

By observation, we can deduce that ∠BDE, ∠CDH, ∠CEH and ∠AEH are all right-angled triangles.


Using the above, we are able to repeat this process of solving for each angle until we have ∠HCA.

To verify that our answer is correct, recall that sum of angles in a polygon is 360°

That means:

∠BDA + ∠DHE + ∠CEH + ∠HCA = 360°

That is, 90+ 128 + 90 + 52 = 360°

See attached images and;

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