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Radda [10]
2 years ago
14

What is the area of the triangle​

Mathematics
1 answer:
Lina20 [59]2 years ago
5 0

Answer:

Use this to answer your question :)

Step-by-step explanation:

The area of a triangle is defined as the total region that is enclosed by the three sides of any particular triangle. Basically, it is equal to half of the base times height, i.e. A = 1/2 × b × h.

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Pina has two equations that she found to be valuable models for her research. She thinks that if she can find the solution of th
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Answer is parallel lines
Reason - same slope (3x) and different y intercept means they will be parallel lines because their slope is the same but they will cross the y axis at different points.

I changed the first equation to y intercept form
y = 3x - 10 to match the other equation
y = 3x - 6
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1/16 in. Converted to mm
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What digit is in the ten-thousands place in the number 81,473
Ugo [173]

Answer:

8

Explanation:

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Find the value for “x”; 2 – 7x = -19
Law Incorporation [45]

Step-by-step explanation:

<em>2</em><em>+</em><em>1</em><em>9</em><em>=</em><em>7x</em>

<em>2</em><em>1</em><em>=</em><em>7x</em>

<em>21</em><em>÷</em><em>7</em><em>=</em><em>7x</em><em>÷</em><em>7</em>

<em>3</em><em>=</em><em>x</em>

<em>.</em><em>.</em>

4 0
3 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
2 years ago
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