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3 years ago

If swing A is shorter in length than swing B.

1 answer:

8 0

A because if you apply Newton's law to this problem, then the longer rope (B) would swing farther but would get to the point of destination slower than A would. Hope this awncered ur problem.

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On a multiple choice test with 17 questions, each question has four possible answer, one of which is correct. For students who g

Virty [35]

Answer:

C. 4.3

Step-by-step explanation:

Given that

n = 17

P = 1/4

Using binomial

Mean = np

Mean = 17 × (1/4)

= 17 × .25

= 4.25

Approximately = 4.3

3 0

3 years ago

Write a real world situation of |x-14|=3

natita [175]

X -14 +14={3+14}
×=17
answer is 17 .

7 0

3 years ago

Help if u don’t mind A)117 B)115 C)130

Alexxandr [17]

Answer:

I believe the answer i B

Step-by-step explanation:

I'm not 100% sure so please correct me if im wrong, sorry if i am

6 0

2 years ago

Please help me out. What is 421 divided by 27

____ [38]

Answer:

15.5925925926

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

The picture of the question in the attached figure

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago