Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)
Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12
By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.
Answer: b=12
We notice it diviides by 3 each time or multiplies by 1/3
common ratio is 1/3
first term is 648
so next 3 terms are 8, 8/3, and 8/9
rule is an=648(1/3)^(n-1)
Answer:
[13, 15, 17, 16, 12]
[16, 12, 17, 13, 15]
[16, 15, 14, 13, 12]
[17, 13, 15, 12, 14]
Step-by-step explanation:
Writing a Python code, I got the answers given, reading from left to right to down. For example, for [13, 15, 17, 16, 12], 13 is the top left circle, 15 is the middle right, 17 is the far right, 16 is the bottom left, and 12 is the bottom right
Answer:
I do not know
Step-by-step explanation:
I think so
