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mrs_skeptik [129]
3 years ago
8

1" title="solve \: the \: following \: problems \: below" alt="solve \: the \: following \: problems \: below" align="absmiddle" class="latex-formula">
please answer it correctly I need It now
please none sense report ​

Mathematics
1 answer:
mezya [45]3 years ago
7 0

Answer:

1. Find the circumference, then multiply that by 120 turns.

Formula for circumference;

C = 2πr

But, we need to find the radius which is 1/2(half) of the diameter, so,

D/2 = R

D = Diameter

R = Radius

20/2 = 10 is the radius.

Plug in values now:-

C = 2(3.14) x 10

C = 6.28 x 10

C = 62.8 is the circumference, now we multiply this by 120 to get the total amount of centimetres it'll go.

62.8(120)

= <u>7,536 cm</u> it'll go.

2. Find the circumference, then multiply that by 750 turns/revolutions.

C = 2πr

Find radius,

D/2 = R

50/2 = 25 is the radius.

Plug in values now:-

C = 2(3.14) x 25

C = 6.28 x 25

C = <u>157 cm</u> it'll go.

3. Same thing, find circumference then compare values.

Given that radius is 10,

Use the formula for circumference;

C = 2πr

Replace values:-

C = 2(3.14) x 10

C = 6.28 x 10

C = <u>62.8 cm</u> is the circumference of the first circle.

Now the second circle, (use same formula)

C = 2πr

Find radius,

D/2 = R

10/2 = 5 is the radius.

Replace values:-

C = 2(3.14) x 5

C = 6.28 x 5

C = <u>31.4 cm</u> is the circumference for the second circle.

Now subtract the second circle's circumference from the first:

62.8 - 31.4

= 31.4, <u>31.4</u> <u>cm</u> is how much greater the second circle is than the first.

4 - 5. Find circumference, (using circumference formula)

C = 2πr

Find radius,

D/2 = R

760/2 = 380

Replace values:-

C = 2(3.14) x 380

C = 6.28 x 380

C = <u>2,386.4 km</u> is the distance he'll travel.

If he wants to travel around it with 2,000 km, he'll need to travel <u>at least once</u>.

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Well for f(x) = 2x²+2

1)
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2)
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4)

the domain of the inverse, well, if two expressions are inverse of each other, say f(x) and g(x), are inverse of each other, the "domain of f(x), is the range of g(x)" and "the range of f(x) is the domain of g(x)"

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5)

surely you know by now, what's the range of the inverse?  well, what's the domain of f(x)? is ℝ, so, that's the range of the inverse then
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