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Nana76 [90]
2 years ago
11

Use the graph or table to find the equation that represents the relationship.

Mathematics
1 answer:
luda_lava [24]2 years ago
3 0

Using the information given in any graph or table, find the slope (m) and y-intercept (b) and substitute their values into y = mx + b, which represents the linear equation.

<h3>What is the Equation that Represents a Linear Graph?</h3>

If we have a graph or table that represents a linear relationship between x and y, we can use a linear equation to represent the graph or table as, y = mx + b.

The graph or table is missing, however, here's how to find the linear equation that represnts the table or graph.

We would find the following:

  • Slope (m) = chnage in y/change in x = unit rate.
  • y-intercept (b) = the initial value or the vaue of y when the value of x is 0.

Therefore, using the information given in any graph or table, find the slope (m) and y-intercept (b) and substitute their values into y = mx + b, which represents the linear equation.

Learn more about linear equation on:

brainly.com/question/15602982

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) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
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