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allochka39001 [22]
3 years ago
10

True or False? The product of 4 negative numbers is negative.

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

It's false because if there is an even amount of negative numbers the product will always be even.

Whitepunk [10]3 years ago
7 0

Answer:

false

Step-by-step explanation:

e.g

(-2) x (-2) = +4

(-2) x (-2) x (-2) = -8

(-2) x (-2) x (-2) x (-2) = +16

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antoniya [11.8K]
The function is h(t) = -16t^2 + 80t + 224, and according to the description of the function in the problem statement, we have the following:

at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:

h(0) = -16(0)^2 + 80(0) + 224=0+0+224=224 (ft), which is the initial height, as expected.


At t=1 (sec), the height would be  h(1) = -16(1)^2 + 80(1) + 224=-16+80+224=288. 

etc.


The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.

This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.


Answer: B) 7 sec



6 0
3 years ago
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If cos(x) = Three-fourths and tan(x) < 0, what is cos(2x)?
makvit [3.9K]

Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

\sin^2(x) + \cos^2(x) = 1sin

2

(x)+cos

2

(x)=1

So we have:

\sin^2(x) + (1/4)^2 = 1sin

2

(x)+(1/4)

2

=1

\sin^2(x) + 1/16= 1sin

2

(x)+1/16=1

Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

2

(x)=15/16

Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

tan(x) < 0

It means that:

sin(x) < 0

So, we have:

\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

15

/4

sin(2x) is then calculated as:

\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)

So, we have:

\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗

4

15

∗

4

1

This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

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Solve for the value of a. .<br> (9a+6°<br> 750
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8 0
3 years ago
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