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ruslelena [56]
3 years ago
6

A jeepney has an original speed of 30 m/s and a final speed of 40 m/s. Compute its

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

1 m/s/s.

Step-by-step explanation:

Acccelaration = rate of change of speed

= (40 - 30) /10

= 10/10

= 1 m/s/s.

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TRAP is a trapezoid. If TR= 17 and PA= 23, then find the length of EF .
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Answer:

20

Step-by-step explanation:

23 + 17 = 40

40 / 2 = 20

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The unit of measure of an area equal to 1 km by 1m
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3 years ago
An incomplete distribution is given below:Variable You are given that the median value is 70 and the total number of items is 20
expeople1 [14]

Answer:

The missing frequencies are x = 8 and y = 43.

Step-by-step explanation:

Median Value =70

Then the median Class =60-80

Let the missing frequencies be x and y.

Given: Total Frequncy = 200 , Median = 46

\left|\begin{array}{c|ccccccc}Value&0-20&20-40&40-60&60-80&80-100&100-120&120-140\\Frequency&12&30&x&66&y&27&14\\$Cumu.Freq&12&42&42+x&108+x&108+x+y&135+x+y&149+x+y\end{array}\right|

From the table

\sum f_i =149+x+y  

Here, n = 200

n/2 = 100

Lower Class Boundary of the median class, l=60

Frequency of the median class(f) =66

Cumulative Frequency before the median class, f=42+x

Class Width, h=10

Median = l + \dfrac{\dfrac{n}{2} - c.f }{f} \times h

70 = 60+ \dfrac{100- 42+x }{66}\times 10\\70 = 60+ \dfrac{58+x }{66}\times 10\\70-60=\dfrac{58+x }{66}\times 10\\10*66=10(58+x)\\58+x=66\\x=66-58\\x=8

200=149+x+y

200=149+8+y

y=200-(149+8)

y=43

Hence, the missing frequencies are x = 8 and y = 43.

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3 years ago
Please help i will give brainliest
RideAnS [48]
The answer would be C because it’s the only fraction that does not equal 0.4
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3 years ago
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