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2 years ago

Pls help me thank you God bless

Mathematics

1 answer:

USPshnik [31]2 years ago

6 0

Answer:

Step-by-step explanation:

10/3 divided by 5/12

10/3 multiple 12/5

So the 3 and 12 will cross out same as 10 and 5 then we will get 8 as an answer

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Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w

aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0

3 years ago

During the first part of a trip, a canoeist travels 96 miles at a certain speed. the canoeist travels 15 miles on the second pa

blondinia [14]

This problem is a problem using
d = r * t
First part of the trip
d = 96 miles
r = ??
t = ??

Second part of the trip
d = 15 miles
r = r - 5
t = 4 - t

Solve for r first.
96/r + 15/(r - 5) = 4 hours multiply through by r and r - 5
96(r - 5) + 15r = 4*(r - 5)(r) Remove the brackets on the left
96r - 480 + 15r = 4*r*(r - 5) Collect like terms on the left.
111r - 480 = 4r(r - 5) Remove the brackets on the right.
111r - 480 = 4r^2 - 20r Bring the left side over to the right side.
0 = 4r^2 - 20r - 111r + 480 Collect like terms.
0 = 4r^2 - 131r + 480

The only way I could do this was to use the quadratic equation.

$\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}$

a = 4

b = - 131

c = 480

$\text{x = }\dfrac{ -(-131) \pm \sqrt{(-131)^{2} - 4*4*480 } }{2*4}$
$\text{x = }\dfrac{ 131 \pm \sqrt{(17161) - 7680 } }{8}$
$\text{x = }\dfrac{ 131 \pm \sqrt{9481 } }{8}$
$\text{x = }\dfrac{ 131 \pm 97.37 }{8}$

x = (131 + 97.38)/8
x = 28.55
x = (131 - 97.37)/8
x = 4.20

4.2 isn't going to work because the slower speed has to be larger than 5, otherwise you will get a negative speed (as this solution will give), so 4.20 is an extraneous solution.

r = 28.55 for the first part of the trip and
r = 23.55 for the second part of the trip.

Check.
Let's see if the times add up to 4
d/r = t
96/28.55 = 3.36
15/22.75 = 0.64

The times do = 4, so the rates are correct.

Answers
r1 = 28.55 for the 96 mile trip.
r2 = 23.55 for the 15 mile trip.

8 0

3 years ago

Use interval notation to express the set of real numbers x that satisfies the inequality (x+2)(x-5) < 0.

azamat

The interval notation to express the set of real numbers <u>x</u> that satisfies the given inequality is -2<x<5. You also can represent it as (-2,5)

<h3>Inequality</h3>

It is an expression mathematical that represents a non-equal relationship between a number or another algebraic expression. Therefore, it is common the use following symbols: ≤ (less than or equal to), ≥ (greater than or equal to), < (less than), and > (greater than).

The solutions for inequalities can be given by: a graph in a number line or numbers.

For solving this exercise, it is necessary to find a number solution for the given inequality.

First, you should find the critical points of the inequality.

x+2=0

x = -2

and

x-5=0

x=5

Write, the intervals in between critical points. Therefore, -2<x<5.