Question

Solve the following equation for x. 12x^2-36x=0

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve for x ~

$\qquad \sf \dashrightarrow \:12 {x}^{2} - 36x = 0$

$\qquad \sf \dashrightarrow \:12 x({x}^{} - 3) = 0$

$\qquad \sf \dashrightarrow \:12x = 0 \: \: or \: \: x - 3 = 0$

$\qquad \sf \dashrightarrow \:x = 0 \: \: or \: \: x = 3$

Therefore, the possible values of x are 0 and 3