Tell which is greater one inch or one centimeter?

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

5 0

Answer:

An inch is greater than a centimeter.

Step-by-step explanation:

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The point (7, 8) is the solution of which of the following systems of equations?

Alex73 [517]

Option 4

Verification:-

$\\ \sf\longmapsto x-7y=-49$

$\\ \sf\longmapsto 7-7(8)=-49$

$\\ \sf\longmapsto 7-56=-49$

$\\ \sf\longmapsto -49=-49$

And

$\\ \sf\longmapsto 10x+9y=142$

$\\ \sf\longmapsto 10(7)+9(8)=142$

$\\ \sf\longmapsto 70+72=142$

$\\ \sf\longmapsto 142+142$

Hence verified

8 0

2 years ago

Read 2 more answers

Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p

Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the sampling distribution of sample proportions (p-hat).

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

$\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058$

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

$\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667$