X 3/2 = 27 solve for x

A bag has some purple marbles and

Lilit [14]

Answer:

p= T-g

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If the coefficient of determination is 0.25 and the sum of squares residual is 180, then what is the value of SSY?

Gennadij [26K]

Answer:

And then $SSY=SS_{total}=\sum_{j=1}^n (y_j-\bar y)^2 =240$

C. 240

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

When we conduct a multiple regression we want to know about the relationship between several independent or predictor variables and a dependent or criterion variable.

If we assume that we have $k$ independent variables and we have $j=1,\dots,j$ individuals, we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^n (y_j-\bar y)^2$

$SS_{regression}=SS_{model}=\sum_{j=1}^n (\hat y_{j}-\bar y)^2$

$SS_{error}=\sum_{j=1}^n (y_{j}-\hat y_j)^2 =180$

And we have this property

$SST==SSY=SS_{regression}+SS_{error}=SSR+180$

If we solve for SSR we got:

$SSR= SSY-180$ (1)

And we know that the determination coefficient is given by:

$R^2 = \frac{SSR}{SSY}$

We know the value os $R^2= 0.25$ and we can replace SSR in terms of SSY with the equation (1)

$R^2 =0.25= \frac{SSY-180}{SSY}= 1-\frac{180}{SSY}$

And solving SSY we got:

$\frac{180}{SSY}=1-0.25=0.75$

$SSY= \frac{180}{0.75}=240$

And then $SSY=SS_{total}=\sum_{j=1}^n (y_j-\bar y)^2 =240$

C. 240

7 0

3 years ago

A box of colored pencils contains exactly 6 red pencils. The probability of choosing a red pencil from the box is 2/7. How many

ZanzabumX [31]

Answer:

B.21

Step-by-step explanation:

Calculator

4 0

3 years ago

PLS HELP <br> NO LINKS OR I WILL REPORT <br> WILL MARK BRAINLIEST

Zanzabum

1. 10 pastries
2. $11
3. 5 miles
4. 0.83 cups
5. 9 pizzas

1. $0.41
2. erik because there is more

3 0

3 years ago

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8

Gekata [30.6K]

First, let $(x,y)$ be a point in our parabola. Since we know that the focus of our parabola is the point (0,8), we are going to use the distance formula to find the distance between the two points:
$\sqrt{(x-0)^{2}+(y-8)^{2}}$

Next, we are going to find the distance between the directrix and the point in our parabola. Remember that the distance between a point (x,y) of a parabola and its directrix, $y=c$ , is: $|y-c|$ . Since our directrix is y=-8, the distance to our point will be:
$|y-(-8)|$
$|y+8|$

Now, we are going to equate those two distances, and square them to get rid of the square root and the absolute value:
$\sqrt{(x-0)^{2}+(y-8)^{2}}=|y+8|$
$(\sqrt{(x-0)^{2}+(y-8)^{2}})^{2}=|y+8|^{2}$
$(x-0)^{2}+(y-8)^{2}=y+8$

Finally, we can expand and solve for $y$ :
$x^2+y^2-16y+64=y^2+16y+64$
$x^{2}-16y=16y$
$32y=x^{2}$
$y= \frac{1}{32} x^2$

We can conclude that t<span>he standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8 is </span> $y= \frac{1}{32} x^{2}$

3 0

3 years ago