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Nitella [24]
3 years ago
8

HURRY PLEASE SOLVE will give brainliest!!!​

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

2

x-9 = -5

2=x 2+x + 4-2=2 2-6+

-4

2

X

<h2>+2= 4 + 62 =66 +9 = 75</h2>
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I don't know why it is faced that way but help plz
Nady [450]

Answer: x > 5

Step-by-step explanation: You need to isolate x. First, distribute the 1/2 into the parentheses. You will get:

4x + x + 2 > 12

Combine like terms.

5x + 2 > 12

Subtract 2 from each side.

5x > 10

Divide by 5 on each side.

X > 2

Since x is by itself, that is the answer.

7 0
4 years ago
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8pq+20qr-16s factorise plz
7nadin3 [17]

Answer:

asd

Step-by-step explanation:

sadasdasdasdasnst465557

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Help please??????????
marishachu [46]
MachineA: y=120x

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3 years ago
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
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Please help me!! do numbers 5-9 thanks PLEASE SHOW WORK ❤ (picture attached)
kenny6666 [7]
5) n - 5 <u>></u> -2
   <u>    + 5   +5</u>
    n      <u>></u> 3

6) 3 + x < 7
   <u> -3        -3</u>
         x  < 7

7) -7y    <u><</u> 14
<u> ÷ -7          ÷ -7
</u>        y  <u> <</u>  -2<u>

</u>8) b/5  >  -1
   <u>× 5      × 5</u>
     b    >  -5
<u />
4 0
3 years ago
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