All categories

2 years ago

HURRY PLEASE SOLVE will give brainliest!!!

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

4 0

x-9 = -5

2=x 2+x + 4-2=2 2-6+

-4

You might be interested in

Solve the quadratic equation by using the quadratic formula. if the solution are not real, enter N/A 3x^2-7x+1=0

Vsevolod [243]

Answer:

$\displaystyle x=\frac{7\pm\sqrt{37}}{6}$

Step-by-step explanation:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-7)\pm\sqrt{(-7)^2-4(3)(1)}}{2(3)}\\\\x=\frac{7\pm\sqrt{49-12}}{6}\\ \\x=\frac{7\pm\sqrt{37}}{6}$

7 0

1 year ago

In 2004 there were 16000 kidney transplants

victus00 [196]

Answer:

not enough to figure out :/

6 0

2 years ago

25 points! SHOW ALL WORK PLZ!

Eva8 [605]

Answer:its 11

Step-by-step explanation:

$:!

7 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):