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3 years ago

Im in nearpod answer show wrk

Mathematics

1 answer:

steposvetlana [31]3 years ago

8 0

Answer:15 boxes with 4 left over have a great day :)

Step-by-step explanation:

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Find the value of each variable

sesenic [268]

Answer:

x=16

y= 100

Step-by-step explanation:

<1 and <3 are vertical angles so they are equal

5x = 80

Divide each side by 5

5x/5 = 80/5

x = 16

Angles 2 and 3 are supplementary since they form a straight line, they will add to 180

<2 + <3= 180

y+80 = 180

Subtract 80 from each side

y+80-80 = 180-80

y= 100

5 0

3 years ago

Sweet T noticed that the ratio of long boards to short boards was 1:4. If there were 35 surfboards at the beach, how many were s

svp [43]

Answer:

Step-by-step explanation:

sum the parts of the ratio 1 + 4 = 5

divide the number of surfboards by 5 to find one part of the ratio

$\frac{35}{5}$ = 7 ← 1 part of the ratio

4 parts = 4 × 7 = 28 ← number of short boards

8 0

3 years ago

Read 2 more answers

What is the perimeter

Yuri [45]

Answer:

the answer is 10 6/3 20/10 1/2

Step-by-step explanation:

5 0

3 years ago

Find the point of intersection (if any) of the following pairs of lines: a) x – 2y +1=0 2x + 3y – 7 = 0 b) x-2y+11=0 -x+2y-13 =

pychu [463]

Answer:

a) (11/7, 9/7)

b) There's no point of intersection

Step-by-step explanation:

a) x - 2y + 1 = 0

2x + 3y - 7 = 0

To find the point of intersection, we need to solve the system of equations and the result will be the point of intersection (x,y)

$x-2y+1=0\\x= 2y-1$

Now we substitute x in the second equation:

$2x+3y-7=0\\2(2y-1)+3y-7=0\\4y-2+3y-7=0\\7y-9=0\\y=9/7$

Now we substitute y in our first equation.

$x-2y+1=0\\x-2(9/7)+1=0\\x-18/7+1=0\\x=18/7-1\\x=11/7$ .

The point of intersection is (11/7, 9/7)

b) x -2y +11 =0

-x + 2y - 13 =0

We are going to follow the same procedure:

$x-2y+11=0\\x=2y-11$

$-(2y-11)+2y-13=0\\-2y+11+2y-13=0\\0y=2\\0=2$

Since this system of equations doesn't have a solution, the system has no point of intersection.

5 0

3 years ago

In order for a function to be one-to-one, no two elements of the range may be paired with the same value of the domain AND no tw

kirza4 [7]

A True
The first condition gives that the function is in fact a function and the second condition makes it a one to one

7 0

4 years ago