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3 years ago

Please answer the one you would like. I’m very bad at math :(

Mathematics

1 answer:

Lana71 [14]3 years ago

7 0

Answer:

The answer for question one is 162 cm

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What is 2 numbers 5/12’s equivalent to

lana [24]

Answer:

10/24, 15/36

Step-by-step explanation:

10/24

15/36

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4 years ago

*GIVING BRAINLIEST 50POINTS*

PilotLPTM [1.2K]

Answer:

1.x^7

2.x^10

3.a^2

4. 5

Step-by-step explanation:

1. x^(5+2)=x^7

2.x^(5*2)=x^10

3.a^(5-3)=a^2

4. 5 * 1=5

8 0

3 years ago

Read 2 more answers

If a factory continuously dumps pollutants into a river at the rate of the quotient of the square root of t and 45 tons per day,

julsineya [31]

<h2>Hello!</h2>

The answer is:

The first option, the amount dumped after 5 days is 0.166 tons.

To solve the problem, we need to integrate the given expression and evaluate using the given time.

So, integrating we have:

$\int\limits^5_0 {\frac{\sqrt{t} }{45} } \, dt=\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \, dt\\\\\int\limits^5_0 {\frac{1}{45} (t)^{\frac{1}{2} } } \ dt=\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt\\\\\frac{1}{45}\int\limits^5_0 {t^{\frac{1}{2} } } } \ dt=(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)\\\\(\frac{1}{45}*\frac{t^{\frac{1}{2}+1} }{\frac{1}{2} +1})/t(5)-t(0)=(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)$

$(\frac{1}{45}*\frac{t^{\frac{3}{2}} }{\frac{3}{2}})/t(5)-t(0)=(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)\\\\(\frac{1}{45}*\frac{2}{3}*t^{\frac{3}{2} })/t(5)-t(0)=(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)\\\\(\frac{2}{135}*t^{\frac{3}{2}})/t(5)-t(0)=(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})\\\\(\frac{2}{135}*5^{\frac{3}{2}})-(\frac{2}{135}*0^{\frac{3}{2}})=\frac{2}{135}*11.18-0=0.1656=0.166$

Hence, we have that the amount dumped after 5 days is 0.166 tons.

Have a nice day!

5 0

4 years ago

oksano4ka [1.4K]

I only know A, I’m sorry but I hope it helps.

A) because the highlighted arc is bigger than a semicircle you already know that it’s a major arc, because a minor arc will always be smaller than a semicircle.
A) Major arc

5 0

3 years ago

Find the value of this experssion x = -9<br><br> x - 3 x + 5?

aalyn [17]

If you are imposing the x=-9 then, the problem would be set up like this:
=-9-3(-9)+5
=-9-(-27)+5
=18+5
=23

8 0

3 years ago

Read 2 more answers