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Naddika [18.5K]

3 years ago

12

a tool set is on sale for $280. the original price of the tool set was $400. what percent of the original price is the sale pric

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2 answers:

Marianna [84]3 years ago

5 0

70%

Hope this helps! :)

______________

ycow [4]3 years ago

3 0

Answer:

30%

Step-by-step explanation:

400 = 100%

4 = 1%

400 - 280 = 120

120 ÷ 4 = 30

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Consider the sequence 2, 5, 10, 17, ...

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A4 means the 4th number
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state whether the following statement is true or false: y= -x2 + 6x - 10 does not intersect the x-axis.

oee [108]

Answer:

True

Step-by-step explanation:

Here, we want to check if the given equation does not intersect the x-axis

if it does not, then it has no real root

If the discriminant is less than zero, then it has no real roots and does not intersect the x-axis

The formula for the discriminant is;

D = b^2-4ac

In the question;

a = -1 , b = 6 , c = 10

so;

D = 6^2-4(-1)(10)

D = 36-40

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At the start of the football game there were 640 fans in the stadium. It begun to rain during halftime, so 10% of the fans went

choli [55]

10% of 640 is 64. So 640-64= 576 fans. Then after the five touchdowns 26% of 576 is 144 . So 576-144= 432 fans left

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3 years ago

I need help with this

n200080 [17]

Multiplication, addition, subtraction

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2 years ago

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(a) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of 1200 regist

Sladkaya [172]

Answer:

n=9604

Step-by-step explanation:

1) Notation and definitions

$X=620$ number of people that would vote for the Republican candidate

$n=1200$ random sample taken

$\hat p=\frac{620}{1200}=0.517$ estimated proportion of people that would vote for the Republican candidate

$p$ true population proportion of people that would vote for the Republican candidate

Me= 0.01 represent th margin of error.

Confidence =0.95 or 95%

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1- p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

The problem says that we need to use $\hat p =0.05$ , and replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.96})^2}=9604$

And rounded we have that n=9604

6 0

3 years ago