Question

What is the temperature of 12.20 mol of gas in a 18.35 l tank at 16.40 atm?

Answer 1

The temperature of the given mole and pressure of gas is 300.6K.

Given the data in the question;

• Amount of gas; $n = 12.20mol$

• Volume of gas; $V = 18.35L$

• Pressure; $P = 16.40atm$

Temperature; $T = \ ?$

The Ideal Gas Law

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that  pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature. It is expressed;

$PV = nRT$

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( $0.08206Latm/molK$ 0

The determine the temperature of the gas, we substitute our given values inro the equation above.

$PV = nRT\\\\T = \frac{PV}{nR}\\ \\T = \frac{16.40atm\ *\ 18.35L }{12.20mol\ * \ 0.08206Latm/molK} \\\\T = \frac{300.94Latm}{1.001132molLatm/molK} \\\\T = 300.6K$

Therefore, the temperature of the given mole and pressure of gas is 300.6K.

Learn more about Ideal Gas Law: brainly.com/question/4147359