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2 years ago

What is the temperature of 12.20 mol of gas in a 18.35 l tank at 16.40 atm?

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1 answer:

NeX [460]2 years ago

3 0

The temperature of the given mole and pressure of gas is 300.6K.

Given the data in the question;

Amount of gas; $n = 12.20mol$

Volume of gas; $V = 18.35L$

Pressure; $P = 16.40atm$

Temperature; $T = \ ?$

<h3>The Ideal Gas Law</h3>

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature. It is expressed;

$PV = nRT$

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( $0.08206Latm/molK$ 0

The determine the temperature of the gas, we substitute our given values inro the equation above.

$PV = nRT\\\\T = \frac{PV}{nR}\\ \\T = \frac{16.40atm\ *\ 18.35L }{12.20mol\ * \ 0.08206Latm/molK} \\\\T = \frac{300.94Latm}{1.001132molLatm/molK} \\\\T = 300.6K$

Therefore, the temperature of the given mole and pressure of gas is 300.6K.

Learn more about Ideal Gas Law: brainly.com/question/4147359

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Yuki888 [10]

Answer:

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Explanation:

She made this error because she included 1.25 with the x variable but did not include the x variable next to 1.49.

The x variable is important because it can keep track of how many bottles were sold of each water and tea.

So, this means <u>Barbara’s equation did not consider the number of bottles of iced tea.</u>

The real equations should be 1.25x + 1.49x = 100

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topjm [15]

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