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Shtirlitz [24]
2 years ago
10

What is the temperature of 12.20 mol of gas in a 18.35 l tank at 16.40 atm?

SAT
1 answer:
NeX [460]2 years ago
3 0

The temperature of the given mole and pressure of gas is 300.6K.

Given the data in the question;

  • Amount of gas; n = 12.20mol
  • Volume of gas; V = 18.35L
  • Pressure; P = 16.40atm

Temperature; T = \ ?

<h3>The Ideal Gas Law</h3>

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that  pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature. It is expressed;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206Latm/molK 0

The determine the temperature of the gas, we substitute our given values inro the equation above.

PV = nRT\\\\T = \frac{PV}{nR}\\ \\T = \frac{16.40atm\ *\ 18.35L  }{12.20mol\ * \ 0.08206Latm/molK} \\\\T = \frac{300.94Latm}{1.001132molLatm/molK} \\\\T = 300.6K

Therefore, the temperature of the given mole and pressure of gas is 300.6K.

Learn more about Ideal Gas Law: brainly.com/question/4147359

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