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Ratling [72]
2 years ago
14

There are six more necromancers than there are

Mathematics
1 answer:
muminat2 years ago
5 0

Answer:

Step-by-step explanation:

let x be necromancers and y be wizards

if you know the amount of wizards and want to find the amount of necromancers. you just use y + 6

but if you know the amount of necromancers and want to find out the amount of wizards you just do x - 6

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2+2-8-*456*7524+7+46426+*545/65/6213-543+3112+91456+210256488765454<br><br> Answer within 10 min
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5 0
3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
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If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

3 0
3 years ago
Solve for n.<br> Q=5n+5z
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q=5n+5z\ \ \ \ \ \ \ |subract\ 5z\\\\q-5z=5n\ \ \ \ \ \ \ |divide\ by\ 5\\\\n=\frac{q-5z}{5}\\\\Answer\ is\ n=\frac{q-5z}{5}
5 0
3 years ago
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