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3 years ago

8

Plz help I might get a F A marching band has 4 rows of trumpets with 10trumpeters in each row.how many trumpeters are in the mar

ching band use the distributive property to solve.PLZ HELP ASAP IT WILL MEAN A LOT TO ME!!!!!

2 answers:

solmaris [256]3 years ago

8 0

4(10)
an unknown amount of trumpeters.
the answer is 40.

almond37 [142]3 years ago

5 0

The answer is 40

i hope this helps and have a great day !!!

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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

Can someone help please :) i’ll mark brilliant

stiks02 [169]

Answer:

X= 23 degrees

Step-by-step explanation:

117 degrees minus 94 equals x

x=23

4 0

3 years ago

Equivalent of (17×4)−35

Thepotemich [5.8K]

17 times 4, you get 68. 68 minus 35, your answer is 33
17*4=68
68-35=33

3 0

3 years ago

Solve the quadratic equation.<br>m^2/15 -3 = 2

Radda [10]

The answer is $5 \sqrt{3}$

<h3>Explanation :</h3>

$\frac{ {m}^{2} }{15} - 3 = 2$

$\frac{ {m}^{2} }{15} = 2 + 3$

$\frac{ {m}^{2} }{15} = 5$

${m}^{2} = 5 \times 15$

${m}^{2} = 75$

$m = \sqrt{75}$

$m = \sqrt{25 \times 3}$

$m = \sqrt{25} \times \sqrt{3}$

$m = 5 \sqrt{3}$

CMIIW

7 0

3 years ago

Sally was walking to Ocean Front Housing Complex, In miles, how far is her distance?

Vanyuwa [196]

Answer:

Sally is 10 miles

The coordinate ofthe deli is (1, -1)

Step-by-step explanation:

✍️Coordinate of Sally = (-3, 2)

Coordinate of Ocean Front = (5, -4)

The distance of Sally to Ocean Front Housing Complex = the distance between point (-3, 2) and (5, -4).

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ , to calculate the distance between (-3, 2) and (5, -4):

$d = \sqrt{(5 -(-3))^2 + (-4 - 2)^2}$

$d = \sqrt{(8)^2 + (-6)^2}$

$d = \sqrt{64 + 36}$

$d = \sqrt{100} = 10$

✅The distance of Sally is 10 miles

✍️the coordinate of Deli would be half the distance between Sally and Ocean Front.

Therefore, use the midpoint formula to calculate the coordinate of the midpoint between Sally (-3, 2) and Ocean Front (5, -4).

Midpoint of (-3, 2) and (5, -4).

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Plug in the values

$M(\frac{-3 + 5}{2}, \frac{2 +(-4)}{2})$

$M(\frac{2}{2}, \frac{-2}{2})$

$M(1, -1)$

✅The coordinate ofthe deli is (1, -1)

8 0

3 years ago