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2 years ago

-3(10) Simplify [Multiplication with integers]

Mathematics

2 answers:

Ivan2 years ago

7 0

Answer:

$\boxed{\sf{-30}}$

Step-by-step explanation:

To solve this problem, all you have to do is solve by order of operations.

PEMDAS stands for:

Parenthesis
Exponents
Multiply
Divide
Add
Subtract

First, remove parenthesis.

Multiply.

-3*10

Solve.

$\sf{-3*10=\boxed{\sf{-30}}$

-30

Therefore, the correct answer is -30.

I hope this helps you! Let me know if my answer is wrong or not.

Eva8 [605]2 years ago

6 0

Answer:

-30

Step-by-step explanation:

it is adding 10 three times, but then you add the negative after

so it is 10+10+10 because you are multiplying it by 3

you could also add 3 ten times because the communitive property

so 3+3+3+3+3+3+3+3+3+3

you would do the same whether the -3 was in parentheses or not

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Read 2 more answers

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and

Brums [2.3K]

Answer:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

$p_v =P(t_9>10.349)=1.34x10^{-6}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=51.6$ represent the sample mean

$s=1.1$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =48$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:

Null hypothesis: $\mu \geq 48$

Alternative hypothesis: $\mu > 48$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

Calculate the P-value

First we find the degrees of freedom:

$df=n-1=10-1=9$

Since is a one-side upper test the p value would be:

$p_v =P(t_9>10.349)=1.34x10^{-6}$

Conclusion

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3 years ago

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-3(10) Simplify [Multiplication with integers]​

-3(10) Simplify [Multiplication with integers]