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2 years ago

A car depreciated $1500 each year it was owned and driven. What type of depreciation is this?

Mathematics

2 answers:

kicyunya [14]2 years ago

7 0

Answer: straight line depriciation

Bumek [7]2 years ago

3 0

It is yearly depreciation

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PLEASE HELP I GIVE THANKS

kari74 [83]

Since the whole length of the rectangle is 8, and the line across isnt exactly in the middle, (but just a little bit farther than the 4 mark) ... Then the correct answer is:
D. 4 1/2 units

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3 years ago

6.Tanya bought a house for $270,000. She paid

nignag [31]

Answer:

75 X 3000 = 225000

225000 + 50000 = 275000

275000 - 270000 = 5000

$5000 more

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2 years ago

Which fraction is bigger 7/8 or 13/15

ivolga24 [154]

Answer:

7/8

Step-by-step explanation:

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3 years ago

Read 2 more answers

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

7 0

2 years ago

Graph the line passing through the given point and having the given slope (0,3), m=4

andriy [413]

Hint :-

To find out the equation of the line we can use the point slope form of the line which is $y - y_1 = m(x-x_1)$

Solution :-

The given point to us is , $(0,3)$ and the slope of the line is 4 . On using the point slope form , we have ,

$\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}$

Hence the equation is 4x - y + 3 = 0 

( for graph , see attachment ) .

3 0

2 years ago