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Grace [21]
3 years ago
10

Complete the square to transform the expression x2 6x 5 into the form a(x − h)2 k. (x 6)2 4 (x 6)2 − 4 (x 3)2 − 4 (x 3)2 4

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0

An equation is formed of two equal expressions. The equation x²+6x+5 into the form a(x − h)²+k is written as (x+3)²-4.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The transformation of the equation from x²+6x+5 into the form a(x − h)²+k can be done in the following steps as shown below,

1. Taking +5 on the right-hand side of the equation,

x^2+6x+5 = 0\\\\x^2+6x = -5

2. Now if we add +9 on both sides of the equation, we will get,

x^2+6x = -5\\\\x^2+6x+9 = -5+9

3. Now we look at the left side of the equation as the square of the binomial expression (x+3).

x^2+6x+9 = -5+9\\\\(x+3)^2 =4

4. Taking +4 from the right side of the equation to the left side of the equation,

(x+3)^2 =4\\\\(x+3)^2 -4=0

Thus, the equation is in the form of a(x − h)²+k, where the value of a is 1, h is -3 and the value of k is -4.

Hence, the equation x²+6x+5 into the form a(x − h)²+k is written as (x+3)²-4.

Learn more about Equation:

brainly.com/question/2263981

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Any perpendicular line has a negative reciprocal slope. So your slope would be 2. The. You would have the equation : y=2x+b. You would then replace the coordinate (5,6) with x and y on your line to solve for b. Your equation would be : y=2x-4
5 0
3 years ago
Read 2 more answers
What is one of the solutions to the following system of equations? y2 x2 = 53 y − x = 5 (−10, −5) (−7, −2) (7, 2) (5, 10).
Aliun [14]

The solution of the system of equation is (-7, -2).

<h2>Given</h2>

The system of the equations;

\rm y^2 + x^2 = 53 \\\\y -x = 5

From equation 1

\rm  y -x=5\\\\y = 5+x

Substitute the value of y in equation 1

\rm y^2+x^2=53\\\\(5+x)^2+x^2=53\\\\25+x^2+10x+x^2=53\\\\2x^2+10x+25-53=0\\\\2 x^2 + 10x - 28 = 0     \\\\Divide \ by \ 2 \ both \ side \ the \ equation\\\\x^2 + 5x - 14 = 0\\\\x^2-7x+2x-14=0\\\\x(x-7) + 2(x-7) =0\\\\(x-7) \ (x+2)=0\\\\x-7=0 \ \ x = 7\\\\x +2 =0 \ \ x=-2

The value of x= 2 is rejected because x = 2 not satisfy the equation.

Substitute 2 for the value of x in equation II

y − x = 5

y – 2 = 5

y = 5 +2

y = 7 (x =2, y =7) … Not included in the options

If x = -7

Substitute the value of x = -7 in the equation

\rm y -x=5\\\\y - (-7)=5\\\\y +7= 5\\\\y = 5-7\\\\y = -2

Hence, the solution of the system of equation is (-7, -2).

To know more about System of Equation click the link given below.

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6 0
2 years ago
Evaluate the question​
mylen [45]

Answer:

A) 5/6

B) -67/30 (or) -2 7/30

A) -9/2 (or) -4 1/2

Step-by-step explanation:

A) 2/3(5)-5/2=3 1/3-5/2 = 10/3-5/2 = 20/6-15/6= 5/6

B) 2/3(2/5)-5/2= 4/15-5/2 = 8/30-75/30 = -67/30

A) 2/3(-3)-5/2=-2-5/2= -4 1/2

7 0
3 years ago
What quadratic function f whose only zero is -6
Mrrafil [7]

Answer:

y=(x+6)^2

Step-by-step explanation:

Bc, the root has to be only -6

there fore x=-6

4 0
3 years ago
What is the least common<br> multiple of 15a² and 3a2?<br> 1.3a2<br> 2.3a3<br> 3.15a2<br> 4.15a3
AveGali [126]

Answer:

1. 3a2

Step-by-step explanation:

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3 years ago
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