Three thousand dollars are invested in an account paying 6% interest, and half that amount is invested at 4%

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

What is 7539 increased by 3200

Tanya [424]

Subtract thats how you get it

5 0

3 years ago

Read 2 more answers

Can I get some help with proofs? Picture is attached

aleksandr82 [10.1K]

Give a reason for each step of the proof.

Given: <1 and <2 are complimentary

<1 is congruent to <3,

<2 is congruent to <4

Prove: <3 and <4 are complimentary

Statements: Reasons:

1. <1 and <2 are complimentary 1.Given

2. m<1 + m<2=90* 2.DEFINITION OF COMPLEMENTARY ANGLES

3. <1 is congruent to <3, <2 is congruent to <4 3.__GIVEN______

4. m<1=m<3, m<2=m<4 4.DEFINITION OF CONGRUENT ANGLES_

5. m<3 + m<2=90* 5. SUBSTITUTION PROPERTY (m<1 is replaced by m<3.)

6. m<3 +m<4=90* 6. DEFINITION OF COMPLEMENTARY ANGLES

7. <3 and <4 are complimentary 7. DEFINITION OF COMPLEMENTARY ANGLES

8 0

3 years ago

Julio believes that the quotient of 6 divided by 1/2 = 3. Explain Julios error and tell how to find the correct answer.

Gnom [1K]

Answer:

it can be written as 6/1 divided by 1/2

then you'll use the keep, switch, flip method. keep 6/1, switch division to multiplication, and flip 1/2 to become 2/1 or 2

now your equation is 6 x 2 = 12

Julio did 6 divided by 2. which could've been fixed if he changed the division sign to multiplication and multiplied

8 0

3 years ago

Simplify the following:

aivan3 [116]

Answer:

A

Step-by-step explanation:

6 0

3 years ago