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Zanzabum
3 years ago
10

30 POINTS HELP ME-

Mathematics
2 answers:
julsineya [31]3 years ago
7 0

Answer:

D

Step-by-step explanation:

D

I just had to do $120/$30= 30

Ray Of Light [21]3 years ago
4 0

Answer:

Number line graph with closed circle on 30 and shading to the right

because you already have 30 dollars and they need at least 120 but if they get more then 120 they can still hold the science fair.

THIS ANSWER ISN'T MINE. I TOOK IT FROM AN ANSWER TO THE SAME QUESTION ANOTHER USER POSTED.

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Hi, What is the volume of this rectangular prism, help pls.
sweet-ann [11.9K]

Answer:

180

Step-by-step explanation:

9x5x4=180

hope this helps :) pls mark me brainliest :)

6 0
3 years ago
Read 2 more answers
Plz help with both plz
melamori03 [73]
<span>Step 1: 0.04 = 4⁄100</span> 
<span>Step 2: Simplify 4⁄100 = 1⁄25</span> 

<span>
</span>
7 0
4 years ago
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15. In triangle ∆PQR, C is the centroid.
Dmitrij [34]

Because C is the centroid, therefore:

Segments PZ = ZR;  RY = YQ; QX = XP<span>

<span>A.
If CY = 10, then </span></span>

PC = 2*CY = 20<span>
PY = PC + CY = 20 + 10 = 30
Answer:      PC = 20</span>      PY = 30

B.
If QC = 10, then

ZC = QC/2 = 5<span>
ZQ = ZC + QC = 5 + 10 = 15
Answer:      ZC = 5</span>        ZQ = 15

<span>C.
<span>If PX = 20
Because the median RX bisects side PQ, therefore PX = QX = 20
PQ = PX + QX = 40
Answer:      <span>PQ = 40</span></span></span>

5 0
3 years ago
What is the area of a rectangle when the two sides are 4200 and 4500 in meters squared
IceJOKER [234]

Answer                                                                                                                           17400

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Using calculus, you can find a function’s maximum or minimum by differentiating and setting the result to zero. Do this for equa
Elenna [48]

Answer:

\dfrac{dx}{d\theta}=\dfrac{2v_0^2\cos2\theta}{g}

x=\dfrac{v_0^2}{g} at \theta=45

Step-by-step explanation:

x=\dfrac{v_0^2\sin2\theta}{g}

Differentiating with respect to \theta means v_0 and g are constants. So we differentiate only the \sin2\theta term.

Assume y=\sin2\theta.

Let u=2\theta.

\dfrac{du}{d\theta}=2

Also, y becomes

y=\sin u

\dfrac{dy}{du}=\cos u

By chain rule,

\dfrac{dy}{d\theta}=\dfrac{dy}{du}\cdot \dfrac{du}{d\theta}

\dfrac{dy}{d\theta}=\cos u\cdot2=2\cos u=2\cos 2\theta

Adding back the constants,

\dfrac{dx}{d\theta} = \dfrac{2v_0^2\cos2\theta}{g}

Equating this to 0,

\dfrac{dx}{d\theta}=\dfrac{2v_0^2\cos2\theta}{g}=0

\cos2\theta=0

2\theta = \cos^{-1}0=90

\theta=45

Using this value of \theta in the expression for x,

x=\dfrac{v_0^2\sin(2\times145)}{g}=\dfrac{v_0^2\sin90}{g}=\dfrac{v_0^2}{g} (since \sin90=1)

7 0
4 years ago
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