All categories

2 years ago

30 POINTS HELP ME-

Mathematics

2 answers:

julsineya [31]2 years ago

7 0

Answer:

Step-by-step explanation:

I just had to do $120/$30= 30

Ray Of Light [21]2 years ago

4 0

Answer:

Number line graph with closed circle on 30 and shading to the right

because you already have 30 dollars and they need at least 120 but if they get more then 120 they can still hold the science fair.

THIS ANSWER ISN'T MINE. I TOOK IT FROM AN ANSWER TO THE SAME QUESTION ANOTHER USER POSTED.

You might be interested in

Write an equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4)

MrRa [10]

Answer:

The equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:

y = 3x-13

Step-by-step explanation:

Given the equation

y + 5 = 3(x - 1)

Writing in the slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept

y = 3(x-1) -5

y = 3x-3-5

y = 3x - 8

Thus, the slope = m = 3

We know that the parallel lines have equal slopes.

So, the slope of a parallel line is also 3

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 3 and the point (3, -4)

y-(-4)=3(x-3)

y+4 = 3x-9

y = 3x-9-4

y = 3x-13

Thus, the equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:

y = 3x-13

5 0

3 years ago

Mary makes f dollars the first day of her new job. She makes $25 ¾ the second day of her job. In total, Mary made $60.00. Solve

Whitepunk [10]

All you have to do is: 60-25.75 = 34.25.

f = 34.25

7 0

3 years ago

Read 2 more answers

BRAINLIEST AWARD NO.2

zzz [600]

Answer:

A whole number first term to render as fifth term a value larger than 10000, should be at least 121

Step-by-step explanation:

The formula is given as recursive since it involves the previous number of the sequence, and defined as:

$a_n=a_{n-1}*3+6$

we also know that the first term is 4

Then in this case, the first five terms are:

$a_1=4\\a_2=4*3+6=18\\a_3=18*3+6=60\\a_4=60*3+6=186\\a_5=186*3+6=564\\$

So if we want to find the first term in the case that the fifth one is greater than 10,000 using this recursive formula, now we have to start backwards, and say that the fifth term is "> 10000" and what the fourth one is.

Notice that if you have this definition for the nth term, we can obtain from it, what the previous term is to find the general rule:

$a_n=a_{n-1}*3+6\\a_n-6=a_{n-1}*3\\\frac{a_n-6}{3} = a_{n-1}\\a_{n-1}=\frac{a_n}{3} -2$

So the rule is to subtract 6 from he term, and divide the subtraction by 3. Then working backwards:

$a_5>10000\\\frac{a_5}{3} -2>\frac{10000}{3} -2\\a_4>=\frac{10000}{3} -2\\\frac{a_4}{3} -2>\frac{\frac{10000}{3}-2}{3}-2 =\frac{10000}{9}-\frac{8}{3} \\a_3>\frac{10000}{9}-\frac{8}{3} \\\frac{a_3}{3} -2>\frac{\frac{10000}{9}-\frac{8}{3} }{3} -2=\frac{10000}{27} -\frac{8}{9} -2=\frac{10000}{27} -\frac{26}{9}\\a_2=\frac{10000}{27} -\frac{26}{9}\\\frac{a_2}{3} -2>\frac{\frac{10000}{27} -\frac{26}{9}}{3} -2=\frac{10000}{81} -\frac{80}{27} \\a_1>\frac{10000}{81} -\frac{80}{27}\approx 120.49$