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katrin2010 [14]
2 years ago
7

At Daniel's Swimwear, there are 76 bikini styles and 4 other types of swimsuit. What percentage of the swimsuit styles are bikin

is?
Mathematics
1 answer:
Alborosie2 years ago
3 0

Total swimwear = 76 bikinis + 4 other types = 80 total


divide number of bikinis by total swimwear then multiply by 100:


76/80 = 0.95

0.95 x 100 = 95%

Answer: 95% are bikinis

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emmasim [6.3K]

Answer:


Step-by-step explanation:

To solve this you just do 14 - 52 then you get 38. Make sure to check your work. 38 + 14 = 52.

7 0
3 years ago
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Cara is a high school student. On average, there are 26 students per class at her school, with a standard deviation of 3 student
aliina [53]

Answer:

B. 97%

Step-by-step explanation:

20 students is -2 standard deviations away from the mean

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8 0
2 years ago
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andrew11 [14]

Answer:

B

Step-by-step explanation:

11 13 18 19 22 25 29 32 37 37 38

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7 0
3 years ago
A professor at a university wants to estimate the average number of hours of sleep the students get during exam week. The profes
balandron [24]

Answer:

The sample size is n = 2

Step-by-step explanation:

From the question we are told that

   The margin of error is  E =4.266

    The standard deviation is  \sigma = 2.539

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  2.58

Generally the sample size is mathematically represented as  

   n = [\frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ] ^2

=>  n = [\frac{2.58  *  2.539  }{4.266} ] ^2

=>  n = 2

6 0
3 years ago
True or false pls no guessing
marshall27 [118]

Answer:

True

Step-by-step explanation:

5 X 5 X 5 = 125 because 5 X 5 would be 25. And 25 X 5 would be 125.

6 0
2 years ago
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