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nexus9112 [7]
3 years ago
13

Is the a system of equations has no solution, the graph of the system are?​

Mathematics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

When you graph the equations, both equations represent the same line. If a system has no solution, it is said to be <em><u>inconsistent</u></em> . The graphs of the lines do not intersect, so the graphs are parallel and there is no solution.

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I need help with this
N76 [4]

Answer:

The x-intercepts are x = 1 , x = 2 , x = 3

The y-intercept is -6

Step-by-step explanation:

* Lets explain how to solve the problem

- To find the x-intercept of a function substitute f(x) by 0

- To find the y-intercept of a function substitute x by 0

- To find the factors of quadratic function use the long division

* Lets solve the problem

∵ f(x) = x³ - 6x² + 11x - 6

∵ (x - 3) is one of its factors

- Use the long division to find the other factors

∵ x³ - 6x² + 11x - 6 ⇒ dividend

∵ x - 3 ⇒ divisor

# Divide the 1st term in the dividend by the 1st term of the divisor

∵ x³ ÷ x = x²

# Multiply x² by the divisor (x - 3)

∵ x²(x - 3) = x³ - 3x²

# subtract it from the dividend

∵ (x³ - 6x² + 11x - 6) - (x³ - 3x²) = (x³ - x³) + (-6x² + 3x²) +11x - 6

∴ The dividend is -3x² + 11x - 6

# Divide the 1st term in the dividend by the 1st term of the divisor

∵ -3x² ÷ x = -3x

# Multiply -3x by the divisor (x - 3)

∴ -3x(x - 3) = -3x² + 9x

# subtract it from the dividend

∵ (-3x² + 11x - 6) - (-3x² + 9x) = (-3x² - 3x²) + (11x - 9x) - 6

∴ The dividend is 2x - 6

# Divide the 1st term in the dividend by the 1st term of the divisor

∵ 2x ÷ x = 2

# Multiply 2 by the divisor (x - 3)

∴ 2(x - 3) = 2x - 6

# subtract it from the dividend

∴ (2x - 6) - (2x - 6) = (2x - 2x) + (-6 + 6) = 0

∴ (x³ - 6x² + 11x - 6) ÷ (x - 3) = x² - 3x + 2

∴ The factors of f(x) are (x - 3)( x² - 3x + 2)

- The factor (x² - 3x + 2) can factorize into two bracket

∵ The last term is positive and the middle term is negative than the

   two brackets have the middle sign (-)

∵ x × x = x² ⇒ 1st terms in the two brackets

∵ 2 × 1 = 2 ⇒ 2nd terms in the two brackets

∵ 2 × x = 2x

∵ 1 × x = x

∵ 2x + x = 3x

∴  (x² - 3x + 2) = (x - 2)(x - 1)

∴ f(x) = (x - 3)(x - 2)(x - 1)

- To find the x-intercept put f(x) = 0

∴ (x - 3)(x - 2)(x - 1) = 0

- That means each bracket = 0

∵ x - 3 = 0 ⇒ add 3 for both sides

∴ x = 3

∵ x - 2 = 0 ⇒ add 2 for both sides

∴ x = 2

∵ x - 1 = 0 ⇒ add 1 for both sides

∴ x = 1

∴ The x-intercepts are x = 1 , x = 2 , x = 3

- To find the y-intercept put x = 0

∵ f(x) = x³ - 6x² + 11x - 6

∵ x = 0

∴ f(0) = 0 - 0 + 0 - 6 = -6

∴ The y-intercept is -6

4 0
3 years ago
Someone please answer! 8th grade math question.
yulyashka [42]

Answer: there is 3 terms

Step-by-step explanation: each term is separated by a sybol (addition, substation, multiplication, etc).

7 0
3 years ago
Complete the square: x^2-8x+21=6<br><br> Please show work
mina [271]

Answer:

x=5 and 3

Step-by-step explanation:

x^2-8x+21=6

x^2-8x+21+16=6+16

(x-4)^2=1

(x-4)=±1, x=5 and 3

5 0
3 years ago
Read 2 more answers
Which system of inequalities is shown?
anzhelika [568]

Answer:

Option C

Step-by-step explanation:

from the graph: y<4

so option A and B are wrong.

also if we choose any points in the area, always x will be bigger than y. so x>y

3 0
3 years ago
Which gases are released into the atmosphere when volcanoes erupt?
Evgen [1.6K]

Answer:

The volcanoes are formed adjacent to a convergent plate boundary, in which the denser plate subducts under a less denser plate. These subducting plates undergoes partial melting at greater depths and the magma is forced to rise up towards the over-riding plate, resulting in the formation of the volcano and chains of volcanoes.

These volcanoes when undergoes eruptions, releases various types of gases. They are such as the Carbon dioxide (CO₂), Water vapor (H₂O), Sulfur dioxide (SO₂), Hydrogen sulfide (H₂S) and Carbon monoxide (CO).

These gases are harmful to the atmosphere as it creases the green house effect thereby increasing the earth's global temperature.

3 0
3 years ago
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