The sample space (list of outcomes) is:
DFNR; DFRN; DRFN; DRNF; DNFR; DNRF;
NFDR; NFRD; NRFD; NRDF; NDRF; NDFR;
RFDN; RFND; RNFD; RNDF; RDFN; RDNF;
FRDN; FRND; FNRD; FNDR; FDRN; FDNR
P(Dave beside Natalie) = 1/2
P(B,G,B,G or G,B,G,B) = 1/3
P(boys in the middle) = 1/6
P(Frida beside Natalie) = 1/2
P(Robbie between Frida & Natalie) = 1/6
P(Natalie between Dave & Robbie) = 1/6
Explanation
Letting D=Dave, R=Robbie, N=Natalie, and F=Frida you get the list of possibilites above.
For P(Dave beside Natalie), look for DN or ND. This appears 12 times out of the 24 possibilities above; 12/24 = 1/2.
For P(B,G,B,G or G,B,G,B), we have the possibilities DFRN, DNRF, RFDN, RNDF, FRND, FDNR, NDFR, NRFD. There are 8 possibilites out of 24; 8/24 = 1/3.
For P(Frida beside Natalie), look for NF or FN. This appears 12 times out of the 24 possibilities; 12/24 = 1/2.
For Robbie between Frida and Natalie, look for FRN or NRF. This appears 4 times out of 24; 4/24 = 1/6.
For Natalie between Robbie and Dave, look for RND or DNR. This appears 4 times out of 24; 4/24 = 1/6.
3 and 4/9 would be the answer to this.
id a is d than c is b butvthey arent equal so the answe is a
Answer:
A.) No
B.) test statistic = - 3.108
Check explanation
Step-by-step explanation:
H0: m = 105 versus H1: m ≠ 105
Sample size, n = 35, since we have a large sample size, greater than 30.
B.)
xbar = 101.9 ; s = 5.9
Test statistic :
T = (xbar - μ) ÷ (s/√n)
T = (101.9 - 105) / (5.9/√35)
T = - 3.1 / 0.9972820
Test statistic = - 3.11
Pvalue from Tstatistic, df = 34
Pvalue = 0.003772( Pvalue calculator)
Pvalue is the probability of obtaining a value more extreme or exactly that of the test statistic.
At α = 0.01
Pvalue < α ; We fail to reject the Null
A+b+c = 131
b = 7 + 2a and c = a - 12
so a + 7+2a + a-12 = 131
then 4a -5 = 131
then 4a = 136
and a = 34....so b= 75 and c = 22....check 34+75+22=131√
