Answer:
1/24
Step-by-step explanation:
Oodoososososo o mi o mi o mi o my ha
1
2
3
6
9
18
27
54
18 is the greatest
For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is
and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
<u>Slope-Intercept:</u>
y + 3 = 6(x + 2) - 3
y + 3 = 6x + 12 - 3
<u> -3 </u> <u> -3 </u>
y = 6x + 12
<u>Standard:</u>
y = 6x + 12
<u>-6x </u> <u>-6x </u>
-6x + y = 12
-1(-6x + y = 12)
6x - y = -12
<u>Graph:</u>
y = 6x + 12
↓ ↓
↓ y-intercept
slope
Start by graphing the y-intercept: (0, 12)
Then count the rise (up 6) and the run (right 1) from the y-intercept: (1, 18)
or
count the rise (down 6) and the run (left 1) from the y-intercept: (-1, 6)