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Ilia_Sergeevich [38]
2 years ago
8

The Perez family bought4 crates of eggs last week. Each crate had 18 eggs. Since then, they have eaten 26 of the eggs. How many

eggs are left?
Mathematics
2 answers:
agasfer [191]2 years ago
8 0

Answer:

There are 46 eggs left

Step-by-step explanation:

18 x 4 = 72 - 26 = 46

Sergeeva-Olga [200]2 years ago
4 0

Answer:

46

Step-by-step explanation:

so what you need to do is 18 times 4 crates then they eaten 26 so its 18 times 4 - 26 welcome

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Yakvenalex [24]

Answer:

B

Step-by-step explanation:

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3 years ago
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Harold's kitten drinks 5/8 cup of water every day. One cup is approximately equal to 236.4 millilitres which measurement is clos
Lapatulllka [165]

Answer:

147.75 milliliters

Step-by-step explanation:

Find 5/8 of 236.4

So 147.75

So Harold’s kitten drinks 147.75 milliliters Of water everyday.

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3 years ago
In a GP the second and fourth terms are 0.04 and I respectively find the common ratio and the first term​
Reptile [31]

Answer:

common ratio=0.5, a1= 0.08

Step-by-step explanation:

r=a3/a2

r=a4/a3

compare both we get:

a3/a2=a4/a3

subtitute a2=0.04 and a4=1

a3/0.04=1/a3

(a3)^2=0.04*1

(a3)^2=0.04

taking square root in both sides

a3=0.02

For r, r=a3/a2

subtitute a3 and a2 above

r=0.02/0.04

r=0.5 common ratio

For a1

r=a2/a1

0.5=0.04/a1

a1=0.04/0.5

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3 years ago
PLEASE HELP! URGENT!
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Answer:

C, I believe!

7 0
3 years ago
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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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