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Firdavs [7]
3 years ago
14

Suppose that the celsius temperature at the point (x,y) in the xy-plane is T(x,y)=xsin(2y) and that distance in the xy-plane is

measured in meters. A particle is moving clockwise around the circle of radius 1 m centered at the origin at a constant rate of 2m/sec.
A) how fast is the temp experienced by the particle changing in degress cel per meter at the point: P(1/2, sqrt(3)/2)
Mathematics
1 answer:
Elanso [62]3 years ago
3 0
1/2 = cos(2*t)sqrt(3) /2 = sin(-2*t)find tfind the time derivative of  x(t), y(t)(-2sin(2*t) , -2cos(2*t) )plug in the t you found to find the velocity vector.
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Step-by-step explanation:

We get two equations here. One for the area and one for the perimeter. The area gives us x×y=50. The perimeter, if we have a rectangle, x+y+x+y=30=2x+2y. For this to work we need to make a simple expression for x or y. Let's go with x here. 2x+2y=30 so x=15-y. if we fill that in the other equation we get (15-y)×y=50 (see picture). y=5 or y=10. If we fill in x×5=50 we get x=10 and vice versa. So the dimensions are 5 centimeters by 10 centimeters

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