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Firdavs [7]
3 years ago
14

Suppose that the celsius temperature at the point (x,y) in the xy-plane is T(x,y)=xsin(2y) and that distance in the xy-plane is

measured in meters. A particle is moving clockwise around the circle of radius 1 m centered at the origin at a constant rate of 2m/sec.
A) how fast is the temp experienced by the particle changing in degress cel per meter at the point: P(1/2, sqrt(3)/2)
Mathematics
1 answer:
Elanso [62]3 years ago
3 0
1/2 = cos(2*t)sqrt(3) /2 = sin(-2*t)find tfind the time derivative of  x(t), y(t)(-2sin(2*t) , -2cos(2*t) )plug in the t you found to find the velocity vector.
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Evaluate each expression. When the answer is not a whole number, write
Marysya12 [62]

Answer:

C

Step-by-step explanation:

2/3

Does this help? I am not 100% sure

3 0
3 years ago
Can someone help me
Fofino [41]

Step-by-step explanation:

1. Right angled triangle , scalene triangle

2. isosceles triangle, obtuse angled triangle

3. equilateral triangle

4. right angled triangle, isosceles triangle

5. scalene triangle, obtuse angled triangle

6. scalene triangle, acute angled triangle

8 0
2 years ago
Read 2 more answers
The function f(x) = { x + 1 is used to complete this Which statements are true of the given function? Check all that apply. tabl
Dmitry [639]

Answer:

Options (1) and (5)

Step-by-step explanation:

Expression that defines the function is,

f(x)=\frac{1}{2}x+\frac{3}{2}

Option 1

f(-\frac{1}{2})=\frac{1}{2}(-\frac{1}{2})+\frac{3}{2}

          =-\frac{1}{4}+\frac{3}{2}

          =-\frac{1}{4}+1+\frac{1}{2}

          =1+\frac{1}{4}

          =1\frac{1}{4}

So, f(-\frac{1}{2} )=-2 is false.

Option 2

f(0) = \frac{1}{2}(0)+\frac{3}{2}

     = \frac{3}{2}

True.

Option 3

f(1) = \frac{1}{2}(1)+\frac{3}{2}

    = \frac{3+1}{2}

    = 2

Therefore, f(1) = -1 is false.

Option 4

f(2)=\frac{1}{2}(2)+\frac{3}{2}

       =1+1+\frac{1}{2}

       =2\frac{1}{2}

Therefore, f(2) = 1 is false.

Option 5

f(4) =\frac{1}{2}(4)+\frac{3}{2}

     =2+\frac{3}{2}

     =\frac{4+3}{2}

     =\frac{7}{2}

True.

Options (1) and (5) are the correct options.

5 0
3 years ago
the vertices of ABC are points A(1,1), B(4,1), and C(4,5). find the cosines of the angles of the triangle.
pickupchik [31]

Answer:

  • cos(A) = 3/5
  • cos(B) = 0
  • cos(C) = 4/5

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between the cosine of an angle and the sides of the triangle.

  Cos = Adjacent/Hypotenuse

__

<h3>Angle A</h3>

In the given triangle, the hypotenuse is AC. The side adjacent to angle A is AB, so its cosine is ...

  cos(A) = AB/AC

  cos(A) = 3/5

__

<h3>Angle B</h3>

The right angle in the triangle is angle B. The cosine of a right angle is 0.

  cos(B) = 0

__

<h3>Angle C</h3>

The side adjacent to angle C is CB, so its cosine is ...

  cos(C) = CB/AC

  cos(C) = 4/5

7 0
2 years ago
Read 2 more answers
Factor the quadratic expression t^2 + 4t - 7
zepelin [54]

Answer:

Not factorable.

Step-by-step explanation:

We have a trinomial (3 terms). We factor by splitting the middle term 4t into factors of -7 (the last term) which add to 4.

-7 = 1 * -7

4t= 1t+-7t doesn't work

4t=-1t+7t doesn't work

This is not factorable.



7 0
3 years ago
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