If you divide the 2 in 3 you get .6 and if you divide 2 in 5 ou get ,4 now add them you and get 1 now add that 1 to 30 your answer should be 31
The answer would be D. If you would like me to show my work I will, please reply if this is the case. I hope this helps you.
Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
Answer: The length of BC is 7
Step-by-step explanation: Assuming the lengths of the opposite sides of the quadrilateral are congruent, then
AB=DC and
AD=BC
Inputting the values of AB, DC and AD as given in the question:
x + 8 = 3x ...(1)
x + 3=? ...(2)
We have to solve for the value of x to get the actual lengths and thus ascertain BD.
From equation (1):
8 = 3x - x
8 = 2x
8/2 = x
Therefore, x = 4.
If x = 4 then equation(2) would be
4 + 3= 7.
Hence, the actual lengths of the quadrilateral are:
AB = 4 + 8. DC = 3(4)
=12. =12.
AD = 4 + 3. AD = BC
= 7. Therefore, BC = 7.
Hence, it is confirmed that quadrilateral ABCD is a parallelogram since both the opposite sides are proven to be congruent.
Answer:
The expected value for a student to spend on lunch each day = $5.18
Step-by-step explanation:
Given the data:
Number of students______$ spent
2 students______________$10
1 student________________$8
12 students______________$6
23 students______________$5
8 students_______________$4
4 students_______________$3
Sample size, n = 50.
Let's first find the value on each amount spent with the formula:
Therefore,
For $10:
For $8:
l
For $6:
For $5:
For $4:
For $3:
To find the expected value a student spends on lunch each day, let's add all the values together.
Expected value =
$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24
= $5.18
Therefore, the expected value for a student to spend on lunch each day is $5.18
