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Soloha48 [4]
2 years ago
5

Which polynomial is in standard form?

Mathematics
1 answer:
Elina [12.6K]2 years ago
8 0

the

first equation is the answer of this question.

explanation

where the xy is in sequence so it is the standard form of polynomial

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Joe and grace are baking cookies they need a total of 2 cups of sugar for the recipe joe has 11/10 cups of sugar and grace has 3
DanielleElmas [232]

Answer:

Step-by-step explanation:

Total amount of sugar needed to bake the cookies is 2 cups. Amount of sugar that Joe has is 11/10 cups of sugar. Amount of sugar that Grace has is 3/4 cups of sugar.

The total amount of sugar that Joe and Grace have won't be enough to bake the cake because the total of 11/10 cups and 3/4 cups is below 2 cups

6 0
3 years ago
Find the x-coordinates where f '(x) = 0 for f(x) = 2x - sin(2x) in the interval [0, 2π].
Serggg [28]

Answer:

The x-coordinates where f '(x) = 0 for f(x) = 2x - sin(2x) in the interval [0, 2π] are: x=0, π, and 2π.


Step-by-step explanation:

f(x)=2x-sin(2x)

f'(x)=[f(x)]'

f'(x)=[2x-sin(2x)]'

f'(x)=(2x)'-[sin(2x)]'

f'(x)=2-cos(2x) (2x)'

f'(x)=2-cos(2x) (2)

f'(x)=2-2 cos(2x)


f'(x)=0, then:

2-2 cos(2x)=0

Solving for x. First solving for cos(2x): Subtracting 2 from both sides of the equation:

2-2 cos(2x)-2=0-2

-2 cos(2x)=-2

Dividing both sides of the equation by -2:

-2 cos(2x) / (-2)=-2 / (-2)

cos(2x)=1

If cos(2x)=1, then:

2x=2nπ

Dividing both sides of the equation by 2:

2x/2=2nπ/2

x=nπ


If n=-1→x=-1π→x=-π, and -π is not in the interval [0,2π], then x=-π is not in the solution.

If n=0→x=0π→x=0, and 0 is in the interval [0,2π], then x=0 is in the solution.

If n=1→x=1π→x=π, and π is in the interval [0,2π], then x=π is in the solution.

If n=2→x=2π, and 2π is in the interval [0,2π], then x=2π is in the solution.

If n=3→x=3π, and 3π is not in the interval [0,2π], then x=2π is not in the solution.


Solution: x=0, π, and 2π.

5 0
3 years ago
What is the distance from the origin to point A graphed on the complex plane below?
Lisa [10]

Answer:

a. square root of 5

b. square root of 13

c. 9

d. 13

Step-by-step explanation:

6 0
3 years ago
(3cosx-4sinx) + (3sinx+4cosx) = 5
Ksenya-84 [330]
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0

Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º      (360º-53.13º=306.87)

sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º

The solutions when  0≤x≤360º are:  36.87º and 306.87º.


3 0
3 years ago
Find the slope of the line
Eddi Din [679]

Answer: A. 3/4

Step-by-step explanation: Rise over Run

8 0
3 years ago
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