Answer:
Step-by-step explanation:
1) In this question we've been given "a", the leading coefficient. and two roots:
2) There's a theorem, called the Irrational Theorem Root that states:
If one root is in this form 
then its conjugate 
. is also a root of this polynomial.
Therefore
3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:
Slope:2
y intercept: 5
so if your test has like a graph the dot will be at y=5
(-1, 0) (0, 3)
these are the coordinates for the graph
Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:
