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3 years ago

PLEASE HELP!!!

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

8 0

B or c for the equation because it is 1-n

Fudgin [204]3 years ago

8 0

$\bf \sum\limits_{n=1}^{6}~(1-n)
\\\\\\
\stackrel{\stackrel{n=1}{1-1}}{0}~~+~~\stackrel{\stackrel{n=2}{1-2}}{-1}~~+~~\stackrel{\stackrel{n=3}{1-3}}{-2}~~+~~\stackrel{\stackrel{n=4}{1-4}}{-3}~~+~~\stackrel{\stackrel{n=5}{1-5}}{-4}~~+~~\stackrel{\stackrel{n=6}{1-6}}{-5}$

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Hi can you help me pleaseeee?)

olganol [36]

<em>So to solve for a variable, you have to isolate that variable onto one side.</em>

Firstly, multiply both sides by j: $h-4=kj$

Next, divide both sides by k and <u>your answer will be: $\frac{h-4}{k}=j$ </u>

Firstly, add g on both sides: $\frac{x}{5}=a+g$

Next, multiply both sides by 5 and <u>your answer will be: $x=5(a+g)$ </u>

Firstly, subtract 5p on both sides: $9c=-4p$

Next, divide both sides by 9 and <u>your answer will be $c=-\frac{4}{9}p$ </u>

3 0

3 years ago

Math definitely isn't my greatest subject, if anyone knows how to do this and can explain it to me please help!

Law Incorporation [45]

Answer:

y-1 = 5/3(x-3)

Choice C

Step-by-step explanation:

slope = (y2-y1)/(x2-x1)

(3,1) (6,6)

m = (6-1)/(6-3)

m = (5/3)

the point slope form of a line is given by

y-y1 = m(x-x1)

You have point (3,1)

y-1 = 5/3(x-3)

Choice C

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3 years ago

Antonia participated in a run-a-thon and raised $265 for her school. She received $25 in donations and an additional $8 for ever

SIZIF [17.4K]

Answer:

Step-by-step explanation:

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2 years ago

The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo

xeze [42]

Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

$\large\boxed{\large\boxed{161}}$

Explanation:

Let's put the information in a table step-by step.

(number of remaining students)

Juniors Seniors

Condition

Initially J S

15 seniors left S - 15

Twice juniors as seniors 2(S - 15)

3/4 of the juniors left 1/4×2(S - 15)
1/3 of seniors left 2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

2/3×(S - 15) - 1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

$2/3\times (S - 15) - 1/4\times 2(S - 15) = 8$

Mutilply all by 12:

$8(S - 15)-6(S - 15)=96$

Distribution property:

$8S-120-6S-90=96$

Addtion property of equalities:

$8S-6S=96+120+90$

Add like terms:

$2S=306$

Division property of equalities:

$S=306/2=153$

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

$2/3\times (S-15)+1/4\times 2(S-15)$