Question

Log2 (10x+5) - log2 5 =5 PLEASE SOLVE AND SHOW WORK THANKS A TON

Answer 1

Answer:

$\sf x =15.5$

Step-by-step explanation:

$\sf log_2\left(10x+5\right)\:-\:log_2\:5\:=5$

$\sf log_2\left(10x+5\right)\:-\:log_2\:5\:=log_2 (32)$

$\sf log_2\left\dfrac{(10x+5)}{5} =log_2 (32)$

$\sf 2x+1 =32$

$\sf 2x+1 -1=32-1$

$\sf 2x =31$

$\sf x =15.5$

Answer 2

Answer:

Step-by-step explanation:

$log_{a}$ $x_{1}$ - $log_{a}$ $x_{2}$ = $log_{a}$ $\frac{x_{1} }{x_{2} }$

$log_{a}$ x = b ⇒ $a^{b}$ = x

~~~~~~~~~~~~~~

$log_{2} (10x+5)$ - $log_{2} 5$ = 5

$log_{2} \frac{10x+5}{5}$ = 5

$\frac{10x+5}{5}$ = $2^{5}$

10x + 5 = 32 × 5

2x + 1 = 32

x = 15.5