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Ede4ka [16]
3 years ago
11

According to the rational root theorem, which number is a potential root of f(x) = 9x8 9x6 – 12x 7?

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

The options of the problem are

A. 0\ B. \frac{1}{7}\ C. 2\ D. \frac{7}{3}

we have

9x^{8} +9x^{6} - 12x +7

we know that

<u>The Rational Root Theorem </u>states that when a root 'x' is written as a fraction in lowest terms

 x=\frac{p}{q} 

p is an integer factor of <u>the constant term</u>, and q is an integer factor of <u>the coefficient of the first monomial</u>.

So

in this problem

the constant term is equal to 7

and the first monomial is equal to 9x^{8} -----> coefficient is 9

therefore

<u>the answer is the option </u>

D. \frac{7}{3}

Alchen [17]3 years ago
5 0
Thank you for posting your math problem here in brainly. <span>According to the rational root theorem, the potential root of f(x) = 9x8 9x6 – 12x 7 are </span><span>±1, ±2, ±4,</span> <span>±<span>13</span>, ±<span>23</span>, ±<span>43</span>, </span> <span>±<span>19</span>, ±<span>29</span>, ±<span>49. I hope my answer helps. </span></span>
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Explain how 4/10÷2 and 4/10×1/2 both equal 2/10.
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2.2 - 0.4i

Step-by-step explanation:

1. Approach

To divide by imaginary number, one must take the fraction and multiply the complex conjugate of the denominator. A complex conjugate is a complex number with its imaginary unit multiplied by (-1). Once one multiplies both the numerator and denominator by the complex conjugate, then the denominator should be a real number (this is because the complex numbers act like binomials when multiplied, and hence the difference of square property works). Now all one has to do is divide every term in the numerator by the real number in the denominator.

2. complex conjugate

As mentioned above, to solve this problem, one has to multiply the numerator and denominator by the complex conjugate of the denominator. That is the complex number in the denominator with its imaginary until multiplied by (-1).

Complex number in the denominator;

(-8 - 6i)

complex conjugate;

(-8 + 6i)

3. Multiplying

Now, one has to multiply the problem's numerator and denominator by the complex conjugate of the denominator. Since a number over itself in fraction format is the same as multiplying by (1), one is allowed to do this;

\frac{-2-i}{-8-6i}

Multiply

\frac{-2-i}{-8-6i} * \frac{-8+6i}{-8+6i}

Distribute

\frac{(-2)(-8) + (-2)(6i) + (-i)(-8) + (-i)(6i)}{(-8)(-8)+(-8)(6i) + (-6i)(-8) + (-6i)(6i)}

4. Simplifying

Now all that is left is to simplify and divide to find the quotient.

=\frac{(-2)(-8) + (-2)(6i) + (-i)(-8) + (-i)(6i)}{(-8)(-8)+(-8)(6i) + (-6i)(-8) + (-6i)(6i)}

=\frac{16 - 12i +8i -6i^{2}}{64-48i+48i-36i^{2}}

Remember the rotations of i, i^{2} = -1

Simplify further

\frac{16-4i+6}{64+36}\\\\=\frac{22-4i}{100}

Divide

2.2 - 0.4i

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