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marishachu [46]
3 years ago
6

A bank is offering 2.5% simple interest on a savings account. if you deposit $5000,how much interest will you earn in one year?​

Mathematics
1 answer:
Elenna [48]3 years ago
3 0

Answer:

$125 you will end up w/ $5125

Step-by-step explanation:

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Triangle ABC, with coordinates A(2, 3), B(3, 5), C(7, 4), is dilated by a scale factor of 2. What are the coordinates of the dil
podryga [215]
Hello,

When you dilate a shape by a scale factor of 2, you simply multiply the coordinates by 2.

Therefore, the points become:
A(2, 3)  ===>  A'(4, 6)
B(3, 5)  ===>  B'(6, 10)
C(7,4)   ===>  C'(14,8)

Good luck,
MrEQ
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4 years ago
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Choose the best answer that represents the property used to rewrite the expression.
cricket20 [7]
Product property is the answer
6 0
3 years ago
What is the mean, variance, and standard deviation of the values? Round to the nearest tenth. 1,9,4,12,13,13
tankabanditka [31]

To compute the mean, you simply have to sum all the elments in the data set and the divide the sum by the number of elements:


M = \frac{1+4+9+12+13+13}{6} = \frac{52}{6} = 8.6


To compute the variance, we first need to compute the distance of each element from the mean. To do so, we build a "parallel" dataset, given by the difference of every value and the mean:


D' = 1-8.6,9-8.6,4-8.6,12-8.6,13-8.6,13-8.6


D' = -7.6, 0.4, -4.6, 3.4, 4.4, 4.4


Now we need those difference squared:


(D')^2 = 57.76, 0.16, 21.16, 11.56, 19.36, 19.36


The variance is the mean of this new vector, so


\sigma^2 = \frac{57.76+ 0.16+ 21.16+ 11.56+ 19.36+ 19.36}{6} = \frac{129.36}{6} = 21.6


Finally, the standard deviation is simply the square root of the variance, so you have


\sigma = \sqrt{21.6} = 4.6

8 0
3 years ago
gavin and marco each have equal sized pieces of rope. gavin uses 1/4 of his rope for an art project. marco uses 1/8 of his rope
marissa [1.9K]

Answer:

Gavin uses more rope.

Step-by-step explanation:

Because 1/4>1/8, since 1/4=0.25 and 1/8=0.125.

5 0
4 years ago
Find the arc length of the given curve between the specified points.
yuradex [85]

Answer:

4.25

Step-by-step explanation:

Given:

f(x) = \frac{x^3}{12} + \frac{1}{x} \\\\Arc Length = \int\limits^a_b {\sqrt{1 + (f'(x))^2}  } \, dx \\f '(x) = \frac{x^2}{6} - \frac{1}{x^2}\\\\f'(x)^2 = (\frac{x^2}{6} - \frac{1}{x^2})^2 = \frac{x^4}{36} +  \frac{1}{x^4} - \frac{1}{3}\\\\1 + f'(x)^2 = \frac{x^4}{36} +  \frac{1}{x^4} + \frac{2}{3}\\\\\= \frac{x^8 + 36 + 12x^4}{36x^4}\\\\= \frac{(x^4 + 6)^2}{36x^4}\\\\=\sqrt{1 + f'(x)^2}  = \sqrt{ \frac{(x^4 + 6)^2}{36x^4}}\\\\= \frac{x^2}{6} + \frac{1}{x^2} \\\\

ArcLength = \int\limits^4_1 {\frac{x^2}{6} + \frac{1}{x^2}  } \, dx \\= (\frac{x^3}{18} -  \frac{1}{x})\limits^4_1\\\\= (\frac{64}{18} - \frac{1}{4}) - (\frac{1}{18} - 1)\\\\= \frac{17}{4}= 4.25

8 0
3 years ago
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