X^2+x-12=0 factors out into (x+4)(x-3) so the answer is: x=-4, x=3
-3 on a number line would look like 3 right from 0.
Let's just say we have a number line. A number line is a line that represents numbers. I'll say the positive side is on the top/left and the negative side (-3) on the bottom/right. -3 is a negative number. There is the sign (-) before 3. That indicates it's a negative number. Since it's a negative and 3, we move 3 down or right.
Answer: Its will be 105
Step-by-step explanation: But this is how you get it 315 divided by 3 = 105 or 9x35=315 divided by 3 =105
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
1 becuse you put the deniminatoe 1
