All categories

3 years ago

The table shows the ratio between the number of packets and the number of seeds of a certain plant contained in them:

Mathematics

1 answer:

vichka [17]3 years ago

8 0

Answer:

the thired grap.

Step-by-step explanation:

it is for the test i toke

You might be interested in

Help me pleaseeeeeeeee

MAVERICK [17]

It Would Be B x+3/x-3

4 0

3 years ago

Read 2 more answers

Which of the following cannot be written as an equation?

Luda [366]

Answer:

Step-by-step explanation:

This answer choice is not correct because u can't write a quote as an equation

Hope this helps u ;)

Pls mak brainlist

4 0

3 years ago

What is the converse of t > r

Anettt [7]

The converse of t > r is r > t

<h3>What is a converse statement?</h3>

A converse statement is determined when both the hypothesis and conclusion are reversed or interchanged.

In this condition, the hypothesis is written as the conclusion and the conclusion is changed to be the hypothesis.

If a conditional statement is written as: x → y

The converse is then written as y → x

Where;

x is the hypothesis
y is the conclusion

Given the expression as;

t > r

We can see that;

The variable 't' is the hypothesis
The variable 'r' is the conclusion

The converse will be;

r > t

Hence, the converse is r > t

Learn more about converse statement here:

brainly.com/question/3965750

#SPJ1

6 0

1 year ago

Activity 4: Performance Task

Nookie1986 [14]

An arithmetic progression is simply a progression with a common difference among consecutive terms.

The sum of multiplies of 6 between 8 and 70 is 390
The sum of multiplies of 5 between 12 and 92 is 840
The sum of multiplies of 3 between 1 and 50 is 408
The sum of multiplies of 11 between 10 and 122 is 726
The sum of multiplies of 9 between 25 and 100 is 567
The sum of the first 20 terms is 630
The sum of the first 15 terms is 480
The sum of the first 32 terms is 3136
The sum of the first 27 terms is -486
The sum of the first 51 terms is 2193

(a) Sum of multiples of 6, between 8 and 70

There are 10 multiples of 6 between 8 and 70, and the first of them is 12.

This means that:

$\mathbf{a = 12}$

$\mathbf{n = 10}$

$\mathbf{d = 6}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{10} = \frac{10}2(2*12 + (10 - 1)6)}$

$\mathbf{S_{10} = 390}$

(b) Multiples of 5 between 12 and 92

There are 16 multiples of 5 between 12 and 92, and the first of them is 15.

This means that:

$\mathbf{a = 15}$

$\mathbf{n = 16}$

$\mathbf{d = 5}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*15 + (16 - 1)5)}$

$\mathbf{S_{16} = 840}$

(c) Multiples of 3 between 1 and 50

There are 16 multiples of 3 between 1 and 50, and the first of them is 3.

This means that:

$\mathbf{a = 3}$

$\mathbf{n = 16}$

$\mathbf{d = 3}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*3 + (16 - 1)3)}$

$\mathbf{S_{16} = 408}$

(d) Multiples of 11 between 10 and 122

There are 11 multiples of 11 between 10 and 122, and the first of them is 11.

This means that:

$\mathbf{a = 11}$

$\mathbf{n = 11}$

$\mathbf{d = 11}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{11}2(2*11 + (11 - 1)11)}$

$\mathbf{S_{11} = 726}$

(e) Multiples of 9 between 25 and 100

There are 9 multiples of 9 between 25 and 100, and the first of them is 27.

This means that:

$\mathbf{a = 27}$

$\mathbf{n = 9}$

$\mathbf{d = 9}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{9} = \frac{9}2(2*27 + (9 - 1)9)}$

$\mathbf{S_{9} = 567}$

(f) Sum of first 20 terms

The given parameters are:

$\mathbf{a = 3}$

$\mathbf{d = 3}$

$\mathbf{n = 20}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{20} = \frac{20}2(2*3 + (20 - 1)3)}$

$\mathbf{S_{20} = 630}$

(f) Sum of first 15 terms

The given parameters are:

$\mathbf{a = 4}$

$\mathbf{d = 4}$

$\mathbf{n = 15}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{15} = \frac{15}2(2*4 + (15 - 1)4)}$

$\mathbf{S_{15} = 480}$

(g) Sum of first 32 terms

The given parameters are:

$\mathbf{a = 5}$

$\mathbf{d = 6}$

$\mathbf{n = 32}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{32} = \frac{32}2(2*5 + (32 - 1)6)}$

$\mathbf{S_{32} = 3136}$

(g) Sum of first 27 terms

The given parameters are:

$\mathbf{a = 8}$

$\mathbf{d = -2}$

$\mathbf{n = 27}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{27} = \frac{27}2(2*8 + (27 - 1)*-2)}$

$\mathbf{S_{27} = -486}$

(h) Sum of first 51 terms

The given parameters are:

$\mathbf{a = -7}$

$\mathbf{d = 2}$

$\mathbf{n = 51}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{51} = \frac{51}2(2*-7 + (51 - 1)*2)}$

$\mathbf{S_{51} = 2193}$

Read more about arithmetic progressions at:

brainly.com/question/13989292

4 0

2 years ago

Read 2 more answers

Installment Buying TV Town sells a big screen smart HDTV for $600 down and monthly payments of $30 for the next 3 years. If the

VikaD [51]

Answer:

(a). $1465.42

(b). $214.58

Step-by-step explanation:

We have been given that installment Buying TV Town sells a big screen smart HDTV for $600 down and monthly payments of $30 for the next 3 years. The interest rate is 1.25% per month on the unpaid balance.

(a) To find the cost of the TV, we will use monthly payment formula.

$R=\frac{Pi}{1-(1+i)^{-n}}$ , where,

R = Periodic payment,

P = Loan amount,

i = Monthly interest rate in decimal form,

n = Number of total payments.

$n=3\times 12=36$

$1.25\%=\frac{1.25}{100}=0.0125$

$30=\frac{P*0.0125}{1-(1+0.0125)^{-36}}$

$30=\frac{0.0125P}{1-(1.0125)^{-36}}$

$30=\frac{0.0125P}{1-0.6394091578134724264}$

$30=\frac{0.0125P}{0.3605908421865275736}$

$10.817725265595827208=0.0125P$

$0.0125P=10.817725265595827208$

$P=\frac{10.817725265595827208}{0.0125}$

$P=865.41802124766617664$

$P\approx 865.42$

We know that total cost of TV would be equal to down payment plus amount of loan that is:

$865.42+600=1465.42$

Therefore, the total cost of the TV would be $1465.42.

(b). First of all, we need to find total amount paid in 3 years by multiplying amount of each monthly payment by 36 (3 years equal to 36 months).

$\$30\times 36=\$1080$

To find the total amount of interest paid, we will subtract amount of loan from total payment.

$\$1080-\$865.42=\$214.58$

Therefore, the total amount paid in interest would be $214.58.

8 0

4 years ago