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3 years ago

I'll mark the best or the first as brainliest.

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

6 0

Answer:

Here the error is 

 $\pi {r}^{2}$ 

It should have been ,

 $2\pi {r}^{2}$ 

Step-by-step explanation:

Corrected formula:

 $2\pi {r}^{2} + 2\pi rh$ 

 $= 2\pi ({5}^{2}) + 2\pi(5)(10.6)$ 

 $= 50\pi + 106\pi$ 

 $= 156\pi$ 

 $= 489.84 {yd}^{2}$ 

 $approx . \: 489.8 {yd}^{2} (ans)$ 

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Slope intercept form of : y=(2/5)x+7

photoshop1234 [79]

The slope intercept IS y=2/5x+7

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3 years ago

Please Help Me Asap I Need Units Too

Lina20 [59]

Hello and Good Morning/Afternoon

Let's take this problem step by step:

To find the rate of change is essentially like finding a line's slope:

⇒ the x-values are the number of sodas

⇒ the y-values are the total costs

⇒ choose two sets of coordinates and find the slope

Let's put that into action

Choose any two points

⇒ (24, 18)

⇒ (28, 21)

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$Rate_.of_.change = \frac{21-18}{28-24} =\frac{3}{4}$

Since the rate of change is total cost over number of sodas

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2 years ago

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w

VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) $Fmax=100Hz$

b) $Fmin=0Hz$

c) $F_r=0.0313$

Step-by-step explanation:

From the question we are told that:

Time $t=32sec$

Frequency $F=200Hz$

Segments $\mu=5$

Generally the equation for Frequency Range is mathematically given by

$Fmax=\frac{F}{2}$

$Fmax=100Hz$

Therefore

a) $Fmax=100Hz$

b) $Fmin=0Hz$

Generally the equation for Frequency Resolution is mathematically given by

$F_r=\frac{F}{N}$

Where

N=The Total dat points

N=Sampling Frequency *Time

$N=200*32$

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$F_r=0.0313$

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3 years ago

Please what is the answer?

nirvana33 [79]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Triangle KJL is inscribed in semicircle O shown below such that JK=6 and JL=11. Which of the following is closest to the radius

lakkis [162]

Uhh, answer choices?

In any case, since $\triangle KJL$ is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, $KL=\sqrt{6^2+11^2}=\sqrt{157}.$ Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so $OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.$

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3 years ago