Answer: 111.72 m^2 if they want round its 112
Is from O to C 14m
A=pixr^2
3.14x14^2= 615.44 m/2 half circle = 307.72
Area of triangle A= 1/2bh. .5x28x14=196
307.72-98=196= 111.72 m^2
Step-by-step explanation:
RS+ST=RT
RS=7y-4
ST=y+5 using RS and RT in the first equation gives you:
7y-4+y+5=RT combine like terms on left side
8y+1=RT, and we are told that RT=28 so:
8y+1=28 subtract 1 from both sides
8y=27 divide both sides by 8
y=27/8
(RS=19 5/8, ST=8 3/8, RT=28)
Answer:
A
Step-by-step explanation:
An angle of the measure 
should have the same measure as an angle measured 
because this is periodic. If we do that, we get the angle: 
Thus, the answer is A.
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
