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vovikov84 [41]
2 years ago
8

I need help this is so confusing

Mathematics
2 answers:
seraphim [82]2 years ago
6 0

so point C would be on Quadrant I

T on Quadrant II, H on Quadrant III and R is not really on a quadrant, the coordinate is on the X axis.

Gre4nikov [31]2 years ago
5 0
Point c is quadrant 2,point T is quadrant 1,point R is x axis , point h is quadrant 3
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50 is 50% of what number? Plz show work in explanation thanks. Again im in middle school i musta misclicked high school instead
erastovalidia [21]

100

50 is half of 100 and 50% is half.

6 0
3 years ago
How to work out 270 ÷ 30
tresset_1 [31]

Answer:

270 ÷ 30 = 9

Step-by-step explanation:

9x3=27

90x3 = 270

27 ÷ 3 = 9

270 ÷ 30 = 9

90 x 3 = 270

30 x 9  = 270

8 0
3 years ago
You want to determine the use of a graphing calculator on a test. is it Experimental or Observational
bija089 [108]

experimental I think probably

5 0
2 years ago
Algebra 2 help!
murzikaleks [220]
<h3>Answer:</h3>
  • x-intercept: 82.75
  • y-intercept: -2.15
<h3>Step-by-step explanation:</h3>

To find the x-intercept, set y=0 and solve.

... 0 = log(12x +7) -3

... 3 = log(12x +7) . . . . add 3

... 1000 = 12x +7 . . . . take the antilog. (10^3 = 1000)

... 993 = 12x . . . . . . . .subtract 7

... 82.75 = x . . . . . . . . divide by 12

To find the y-intercept, set x=0 and solve.

... y = log(12·0 +7) -3

... y = log(7) -3 . . . . . . simplify

... y ≈ 0.85 -3 = -2.15 . . . . use a calculator for the log function

4 0
3 years ago
1. In ABC, C is a right angle and BC = 11. If B = 30°, find AC. (1 point)
faltersainse [42]

Answer:

AC=\frac{11\sqrt{3}}{3}

Step-by-step explanation:

Given that triangle ABC is a right angle triangle. Where angle C is a right angle. Also we have been given that BC = 11, B = 30°. Now we need to find the value of AC.

Apply formula:

\tan\left(\theta\right)=\frac{opposite}{adjacent}

\tan\left(B\right)=\frac{AC}{BC}

\tan\left(30^o\right)=\frac{AC}{11}

\frac{1}{\sqrt{3}}=\frac{AC}{11}

\frac{11}{\sqrt{3}}=AC

AC=\frac{11}{\sqrt{3}}

or

AC=\frac{11}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}

or

AC=\frac{11\sqrt{3}}{3}

Hence final answer is AC=\frac{11\sqrt{3}}{3}.

7 0
3 years ago
Read 2 more answers
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