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r-ruslan [8.4K]
3 years ago
13

In his free time, Gary spends 9 hours per week on the internet and 14 hours per week playing video games. If Gary has five hours

of free time per day, approximately what percent of his free time is spent on the internet and playing video games?
Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

40 % playing video games and 25.71 % on the internet

Step-by-step explanation:

5 hours a day time 7 days a week equals 35

14 hours of video game hours divide by 35 hours in the week equals 0.40

move the decimal 2 places to the left to get a percentage = 40%

9 hours of internet divide by 35 hours in the week equals 0.2571428...

move decimal 2 places to the left and round up to the tenths and 25.71%

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A box contains two purple marbles nine orange marbles and seven yellow marbles if you pick two without looking what is the proba
maw [93]

Answer:

1/4

Step-by-step explanation:

First, add up the marbles:

2 + 9 + 7  = 18

Multiply by 2 because you pick two:

18 × 2 = 36

Simplify:

9/36 = 3/12 = 1/4

Hope this helped.

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Help! <br><br><br> How to get over a huge crush
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3 years ago
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What is the GCF of -2xy and -9y
NNADVOKAT [17]

Answer:

- y(2x + 9)

Step-by-step explanation:

The GCF doesn't have to be a number. In this case, it is -y because both the -2xy and -9y share it. It's also easier when you take out a negative. Once you take the GCF out, your new expression should be:

- y(2x + 9)

5 0
3 years ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

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3 years ago
(2g+9h-5)-(6g-4h+2)<br><br>g=-2<br>h=5
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3 years ago
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