There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
B. 6 -4 0 3 1
There is no x^2 term so we use zero instead
Answer: 0.3077
Explanation: In a standard deck of cards, there are 52 cards. They are broken down into suits (4 of them: Spades, Hearts, Diamonds, Clubs) of 13 cards each. Each suit has 13 ordinal cards (A, 2 through 10, Jack, Queen, King).
Here we're asked to draw a card at random and find the probability of drawing either a diamond or a 7.
With probability, we look at the fraction of ways we can achieve some condition (the numerator) over the number of ways we can do something (the denominator).
Our denominator here is 52 - the number of cards from which we can pull 1.
Our numerator is both all the diamonds, 13 cards, and all the sevens, 4 cards, but we need to subtract 1 to account for the double counting of the 7 of diamonds.
In all we get: 13+4−1/52=16/52=4/13≈0.3077
Hope this helps... Stay safe and have a great day/night!!!
<span>16<span>x2</span>−4x−4x+1=4x(4x−1)−1(4x−1)=<span>(4x−1)</span>(4x−1)=<span><span>(4x−1)</span>2</span></span><span>
Length of each side=4x-1</span>
