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Anika [276]
2 years ago
15

I need help on this question I’m confused I think a &b are the same and c &d are different but I’m not to sure !

Mathematics
1 answer:
Nina [5.8K]2 years ago
3 0
<h3>Answer:  They're all the same</h3>

====================================================

Reason:

2^6 means we have 6 copies of "2" multiplied out as shown in choice B. That explains how A and B are the same, and we can say

2^6 = (2*2*2)*(2*2*2)

The parenthesis are optional, but I find they're handy to count the '2's easier.

----------------

Now notice that

2^3 = 2*2*2

So,

2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2^3)*(2^3)\\\\2^6 = (2^3)^2\\\\

The last step is possible because we have two copies of 2^3 multiplied together.

This shows that choice C is equivalent to A and B.

-------------------

Lastly,

2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2*2)*(2*2)*(2*2)\\\\2^6 = (2^2)*(2^2)*(2^2)\\\\2^6 = (2^2)^3\\\\

The jump to the last step is possible because we have three copies of 2^2 multiplied together.

This shows choice D is equivalent to the others.

All four expressions are the same.

They represent different ways to say the same number. That number being 64.

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1.2-0.8

Step-by-step explanation:

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2 years ago
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Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is
pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar  and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt  

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0
3 years ago
Jaime is 2 years older than Alejandra. In 5 years the sum of their ages will be 80. How old is Jaime now?
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Answer:

20 age This is right answer

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How many solutions does this equation have?
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