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nexus9112 [7]
3 years ago
13

What is true of the graph of two lines 3y-8=-5x and 6y=-10x+16

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

Both lines are equal (they are the same)

<em></em>

Step-by-step explanation:

Given

3y - 8 = -5x

6y = -10x + 16

Required

What is true about graph of both lines

<em>Questions like this are better solved when there's option(s) to select from. However, some of the properties of line equation that I'll consider are to check  if both lines are either parallel or perpendicular</em>

<em />

To do this,

The first thing to do is to calculate the slope of both lines

3y - 8 = -5x

Add 8 to both sides

3y - 8 + 8 = -5x + 8

3y = -5x + 8

Divide both sided by 3

\frac{3y}{3} = -\frac{5x}{3} + \frac{8}{3}

y = -\frac{5x}{3} + \frac{8}{3}

The slope of the line is the coefficient of x;

Slope = -\frac{5}{3}

Solve for the y intercept; <em>Let x = 0</em>

y = -\frac{5 * 0}{3} + \frac{8}{3}

y = 0 + \frac{8}{3}

y = \frac{8}{3}

Solve for the x intercept; <em>Let y = 0</em>

0 = -\frac{5x}{3} + \frac{8}{3}

Subtract \frac{8}{3} from both sides

0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}

- \frac{8}{3} = -\frac{5x}{3}

Subtract both sides by -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = x

\frac{3}{5} * \frac{8}{3} = x

\frac{8}{5} = x

x = \frac{8}{5}

------------------------------------------------------------------------------------------------------

6y = -10x + 16

Divide both sides by 6

\frac{6y}{6} = -\frac{10x}{6} + \frac{16}{6}

y = -\frac{10x}{6} + \frac{16}{6}

Simplify fractions to lowest term

y = -\frac{5x}{3} + \frac{8}{3}

The slope of the line is the coefficient of x;

Slope = -\frac{5}{3}

Solve for the y intercept; <em>Let x = 0</em>

y = -\frac{5 * 0}{3} + \frac{8}{3}

y = 0 + \frac{8}{3}

y = \frac{8}{3}

Solve for the x intercept; <em>Let y = 0</em>

0 = -\frac{5x}{3} + \frac{8}{3}

Subtract \frac{8}{3} from both sides

0 - \frac{8}{3} = -\frac{5x}{3} + \frac{8}{3} - \frac{8}{3}

- \frac{8}{3} = -\frac{5x}{3}

Subtract both sides by -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = -\frac{5x}{3} * -\frac{3}{5}

-\frac{3}{5}*- \frac{8}{3} = x

\frac{3}{5} * \frac{8}{3} = x

\frac{8}{5} = x

x = \frac{8}{5}

-------------------------------------------------------------------------------------------------------

By comparing the slope, x intercept and y intercept of both lines;

It'll be observed that they have the same slope, x intercept and y intercept

<em>This implies that both lines are equal; in other words, they are the same.</em>

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Step-by-step explanation:

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PLEASE HELP ME SOLVE
kirill115 [55]

The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .

In the question ,

it is given that

the time taken to vacate the stadium = 20 minutes

number of exits = 25 exits

capacity of the stadium = 25000 spectators .

given that ,

time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .

time taken ∝ number of spectators ∝ 1/number of exits .

to remove the proportionality sign , we write the constant

time taken = k * (number of spectators)/(number of exits) .

20 = k * 25000/25

20 = k * 1000

k = 20/1000

k = 2/100

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So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula

time taken = (0.02)*(21000/15)

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Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28  minutes .

Learn more about Equation here

brainly.com/question/23633125

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