4 accidents.
20 accidents divided by 5 years gives you the unit rate of 4 accidents per year.
You'd probably need to divide 56 by 7 which gives you 8
4,000,000,000 + 700,000,000 + 0 + 0 + 900,000 + 30,000 + 0 + 0 + 0 + 2
your answer would be 33.
step 1
2(+14)−1(2−5)
2+28−1(2−5)
step 2 distribute
2+28−1(2−5)
2+28−2+5
step 3 then add the numbers
2+28−2+5
2+33−2
combine
2+33−2
ANSWER IS
33
Answer:
NO
Step-by-step explanation:
The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:
- N: The number of observations in the population.
- n: The number of observations in the sample.
- The way that the random sample is chosen.
We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is
μ_x=p
σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]
In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:
σ_x = σ / sqrt(n).
