The tangent to 
at the point (0, 5) has a slope equal to the derivative evaluated at 
.
This tangent passes through the point (0, 5), so its equation is
The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is
Answer:
damm its tuff to not know anything
Step-by-step explanation:
Answer:
Student 2 and Student 3
Step-by-step explanation:
Student 2
-(5r - 3s + 1)
= - 5r +3s - 1
Student 3
= - 5r +3s - 1
9514 1404 393
Answer:
D
Step-by-step explanation:
The leading term is of odd degree and negative coefficient. The odd degree tells you the end behaviors will have opposite signs. The negative coefficient tells you the left end behavior will be positive, and the right end behavior will be negative.
