Question

Which equation could john solve to find w, the greatest width in centimeters he can use for the mosaic? w(w – 2) = 48 w(w 2) = 48 2w(w – 2) = 48 2w(w 2) = 48

Answer 1

The equation solved by the John to find w, the greatest width in centimeters he can use for the mosaic, is w(w + 2) = 48.

How to find the area of a rectangle?

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

$A=a\times b$

Here, (a)is the length of the rectangle and (b) is the width of the rectangle

The area of the tile is 48 square cm. John wants to make the mosaic with this tile having the length 2 cm longer than the width.

Let the width of the rectangle mosaic is w cm. Thus, the length of it is,

$l=w+2$

As the area of a rectangle is the product of its length and width and Tte area of the tile is 48 square cm. Thus,

$A=l\times w\\48=(w + 2)\times w \\48=w(w+2)\\w(w+2)=48$

The equation which John solve to find w, the greatest width in centimeters he can use for the mosaic is

$w(w+2)=48$

Learn more about the area of rectangle here;

brainly.com/question/11202023

Answer 2

Answer:

B. w(w + 2) = 48

Step-by-step explanation:

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