Here is the solution of the given problem above.
First, let's analyze the question.
Given: 1 bag = 9/10 pound
2/3 bag = ? pound
What we are going to do is to divide 9/10 pound to 3.
so 9/10 divided by 3 and we get 9/30 and to simplify that, 3/10.
So per 1/3 of the bag, there is 3/10 pound.
To get the weight for 2/3 of the bag, we multiply 3/10 by 2 and we get 6/10 or to simplify it, it is 3/5. Therefore, the 2/3 bag weights 3/5 pound. Hope this answer helps.
Answer:
y = (-3/2)x + 7
Step-by-step explanation:
3x + 2y = -4 (rearrange to slope intercept form y = mx + b)
2y = -3x - 4
y = (-3/2) x - 2
comparing this to the general form of a linear equation : y = mx + b
we see that slope of this line (and every line that is parallel to this line),
m = -3/2
if we sub this back in to the general form, we get:
y = (-3/2)x + b
We are still missing the value of b. To find this, we are given that the point (4,1) lies on the line. We simply substitute this back into the equation and solve for b.
1 = (-3/2)4 + b
1 = -6 + b
b = 7
substituting this back into the equation:
y = (-3/2)x + 7
Answer:
5/6
Step-by-step explanation:
To add fraction, find LCD and then combined
Answer:
1
Step-by-step explanation: 0. 1 is a pure repeating bicimal with a repeating cycle of one digit, so the fraction it converts to is 1/1; in other words, 1
