Answer:
Smaller Number = 10
Larger Number = 33
Step-by-step explanation:
Let the smaller number be "x" and the larger number be "y"
5 TIMES smaller is SUBTRACTED from TWICE larger, the result is 16, we can write:
2y - 5x = 16
and
Larger increased by 3 TIMES SMALLER, result is 63, so we can write:
y + 3x = 63
We can write this in terms of x, as:
y = 63 - 3x
Now we put this in equation 1 and solve for x first:
2y - 5x = 16

Now,
y = 63 - 3x
y = 63 - 3(10)
y = 63 - 30
y = 33
Smaller Number = 10
Larger Number = 33
Answer:
= 26/23
Step-by-step explanation:
5 - v < 6, 5 - v >= 0
-5 + v < 6, 5 - v < 0
1) - v < 6 -5 (move 5 to the right side and then multiply by -1 both sides of the inequality)
v > -1 (don't forget that here v <= 5)
2) v < 6 + 5 (move -5 to the right side)
v < 11 (here v should be more than 5)
so from 1) you get that v is from -1 to 5 inclusive (-1;5]
and from 2) you get that v is from 5 to 11 (5;11)
so by adding up results from 1) and 2) you get v is (-1; 11)
answer: (-1; 11)